Chemistry-
General
Easy

Question

2-methoxy butane is obtained by reacting diazomethane with

  1. 2-butanol
  2. 1-butanol
  3. 2-butanone
  4. Butanal

The correct answer is: 2-butanol

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Related Questions to study

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The figure shows a circular path of a moving particle. If the velocity of the particle at same instant is v equals negative 3 stack stack i with dot on top with hat on top minus 4 stack stack j with dot on top with hat on top, through which quadrant is the particle moving when clockwise and anti-clockwise respectively

The figure shows a circular path of moving particle. At any instant velocity of particle.

v equals negative 3 stack stack i with dot on top with hat on top minus 4 stack stack j with dot on top with hat on top equals left parenthesis negative 3 comma negative 4 right parenthesis (In coordinate from).
The coordinates of velocity show that particle is in 3rd quadrant at that instant. While moving clockwise particle will enter into 4th quadrant and these into 3rd and while moving anticlockwise particle will enter into 2nd quadrant and then into 3rd quadrant.
therefore 4 t h blank a n d blank 2 n d blank q u a d r a n t s.

The figure shows a circular path of a moving particle. If the velocity of the particle at same instant is v equals negative 3 stack stack i with dot on top with hat on top minus 4 stack stack j with dot on top with hat on top, through which quadrant is the particle moving when clockwise and anti-clockwise respectively

physics-General
The figure shows a circular path of moving particle. At any instant velocity of particle.

v equals negative 3 stack stack i with dot on top with hat on top minus 4 stack stack j with dot on top with hat on top equals left parenthesis negative 3 comma negative 4 right parenthesis (In coordinate from).
The coordinates of velocity show that particle is in 3rd quadrant at that instant. While moving clockwise particle will enter into 4th quadrant and these into 3rd and while moving anticlockwise particle will enter into 2nd quadrant and then into 3rd quadrant.
therefore 4 t h blank a n d blank 2 n d blank q u a d r a n t s.
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If a stone s to hit at a point which is at a distance d away and at a height h above the point from where the stone starts, then what is the value of initial sped u, if the stone is launched at an angle Q?

h equals open parentheses u sin invisible function application theta close parentheses t minus fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent
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u equals fraction numerator d over denominator cos invisible function application theta end fraction square root of fraction numerator g over denominator 2 left parenthesis d tan invisible function application theta minus h right parenthesis end fraction end root

If a stone s to hit at a point which is at a distance d away and at a height h above the point from where the stone starts, then what is the value of initial sped u, if the stone is launched at an angle Q?

physics-General
h equals open parentheses u sin invisible function application theta close parentheses t minus fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent
d equals open parentheses u cos invisible function application theta close parentheses t blank o r blank t equals fraction numerator d over denominator u cos invisible function application theta end fraction
h equals u sin invisible function application theta. fraction numerator d over denominator u cos invisible function application theta end fraction minus fraction numerator 1 over denominator 2 end fraction g. fraction numerator d to the power of 2 end exponent over denominator u to the power of 2 end exponent cos to the power of 2 end exponent invisible function application theta end fraction
u equals fraction numerator d over denominator cos invisible function application theta end fraction square root of fraction numerator g over denominator 2 left parenthesis d tan invisible function application theta minus h right parenthesis end fraction end root
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