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An endothermic reaction with high activation energy for the forward reaction is given by the diagram:

  1.      
  2.      
  3.      
  4.      

The correct answer is:

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Graph between concentration of the product' x' and time' t' for A rightwards arrow Bis given ahead:
The graph between negative fraction numerator d left square bracket A right square bracket over denominator d t end fractionand time wil1 be of the type:

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The graph between negative fraction numerator d left square bracket A right square bracket over denominator d t end fractionand time wil1 be of the type:

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Following is the graph between left parenthesis a minus x right parenthesis to the power of negative 1 end exponent and time t for second order reaction. theta equals t a n to the power of negative 1 end exponent invisible function application left parenthesis 1 divided by 2 right parenthesis semicolon O A equals 2 L m o l to the power of negative 1 end exponent hence rate at the start of reaction will be:

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Following is the graph between log tll2 and log a (a = initial concentration) for a given
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For the reaction N H subscript 4 end subscript superscript plus end superscript plus O C N ⟶ N H subscript 2 end subscript C O N H subscript 2 end subscript the probable mechanism is,
table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell NH subscript 4 superscript plus plus OCN to the power of minus not stretchy rightwards harpoon over leftwards harpoon NH subscript 4 OCN end cell row cell text  and  end text space of 1em NH subscript 4 OCN not stretchy ⟶ NH subscript 2 CONH subscript 2 space of 1em text  (slow)  end text end cell end table The rate law will be:

For the reaction N H subscript 4 end subscript superscript plus end superscript plus O C N ⟶ N H subscript 2 end subscript C O N H subscript 2 end subscript the probable mechanism is,
table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell NH subscript 4 superscript plus plus OCN to the power of minus not stretchy rightwards harpoon over leftwards harpoon NH subscript 4 OCN end cell row cell text  and  end text space of 1em NH subscript 4 OCN not stretchy ⟶ NH subscript 2 CONH subscript 2 space of 1em text  (slow)  end text end cell end table The rate law will be:

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