Chemistry
Grade-9
Easy

Question

Calculate the following for 49 gm of H­2SO4.

  1. a-3, b-1, c-2, d-4
  2. a-1, b-2, c-3, d-4
  3. a-2, b-3, c-4, d-1
  4. a-1, b-2, c-4, d-3

hintHint:

Molecular mass of H2SO4 = 2(1) + 32 + 4(16) = 98g

The correct answer is: a-3, b-1, c-2, d-4


    Molecular mass of H2SO4 = 2(1) + 32 + 4(16) = 98g
    Number of moles is 49 g = 49 divided by 98 = 0.5
    In 1 mole number of molecules = 6.022 cross times 1023, in 0.5 mole number of molecules = (6.022 cross times 1023divided by 0.5 = 3.011 cross times 1023
    1 mole contains 50 electrons (2 + 16 + 32), as atomic number is equal to number of electrons. Therefore, 3.011 cross times 1023 molecules contains 50cross times3.011 cross times 1023 = 1.5055 cross times 1025 e-
    1 mole has 2 cross times 6.022 cross times 1023 H atoms, 0.5 moles have 6.022 cross times 1023 atoms.

    a-3, b-1, c-2, d-4

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