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    Chemistry-
    General
    Easy

    Question

    Energy of an electron in Bohr’s nth orbit is.......

    1. fraction numerator n to the power of 2 end exponent h to the power of 2 end exponent over denominator 4 pi to the power of 2 end exponent m z e to the power of 2 end exponent end fraction    
    2. fraction numerator negative 2 pi to the power of 2 end exponent z to the power of 2 end exponent m e to the power of 4 end exponent over denominator n to the power of 2 end exponent h to the power of 2 end exponent end fraction    
    3. fraction numerator negative 2 pi z e to the power of 2 end exponent over denominator n h end fraction    
    4. fraction numerator negative 2 pi z to the power of 2 end exponent m e to the power of 4 end exponent over denominator h to the power of 3 end exponent c end fraction    

    The correct answer is: fraction numerator negative 2 pi to the power of 2 end exponent z to the power of 2 end exponent m e to the power of 4 end exponent over denominator n to the power of 2 end exponent h to the power of 2 end exponent end fraction

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