Chemistry
Grade-9
Easy
Question
Find the weight of water present in 1.61 g of Na2SO4 .10H2O?
- 0.8gm
- 0.9gm
- 10gm
- 0.7gm
Hint:
For 1 mole 180g of water is present.
The correct answer is: 0.9gm
Molecular mass of Na2SO4.10H2O = 2(23) + 32 + 4(16) + 10(18) = 322 g, Where atomic mass of Na, S,O are 23g, 32g, 16g respectively and molecular mass of H2O is 18g.
For 1 mole of Na2SO4.10H2O, 180g of water is present.
Number of moles in 1.61g = 1.61 
322 = 0.005.
The weight of water present in 1.61 g of Na2SO4 .10H2O = (0.005 
180) g = 0.9 gm
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