Chemistry
Grade-8
Easy
Question
For the given reaction, match column I with column II and mark the correct option from the codes given below.
| Column A |
Column B |
| (a) Oxidizing agent |
(i) H2 |
| (b) Reducing agent |
(ii) 4 |
| (c) x |
(iii) 3 |
| (d) y |
(iv) Fe3O4 |
- (a) - (i), (b) - (iv), (c) - (iii), (d) - (ii)
- (a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)
- (a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)
- (a) - (i), (b) - (iv), (c) - (ii), (d) - (iii)
Hint:
(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
The correct answer is: (a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)
Oxidizing agent - Fe3O4
Reducing agent - H2
x - 4 ; y - 3
Fe3O4 + 4H2 ---> 3Fe + 4H2O
8H0 - 8e- ---> 8HI ; oxidation
3Fe8/3 + 8e- ---> 3Fe0 ; reduction
H2 is a reducing agent, Fe3O4 is an oxidizing agent .
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