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For the reaction N H subscript 4 end subscript superscript plus end superscript plus O C N ⟶ N H subscript 2 end subscript C O N H subscript 2 end subscript the probable mechanism is,
table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell NH subscript 4 superscript plus plus OCN to the power of minus not stretchy rightwards harpoon over leftwards harpoon NH subscript 4 OCN end cell row cell text  and  end text space of 1em NH subscript 4 OCN not stretchy ⟶ NH subscript 2 CONH subscript 2 space of 1em text  (slow)  end text end cell end table The rate law will be:

  1. rate =k open square brackets N H subscript 2 end subscript C O N H subscript 2 end subscript close    
  2. rate = k open square brackets N H subscript 4 end subscript close square brackets to the power of plus end exponent left square bracket O C N right square bracket to the power of minus end exponent    
  3. rate = k open square brackets N H subscript 4 end subscript O C N close square brackets    
  4. none of these    

The correct answer is: rate = k open square brackets N H subscript 4 end subscript close square brackets to the power of plus end exponent left square bracket O C N right square bracket to the power of minus end exponent

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