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Chemistry

Grade-9

Easy

Question

The amount of Sodium bicarbonate that is required for obtaining 0.56L of carbon dioxide gas as STP is:

0.42 gm
4.2 gm
420 gm
0.40 gm

hint Hint:

2 moles(168g) of sodium bicarbonate is equivalent to 22.4L of carbon dioxide at STP.

The correct answer is: 0.42 gm

2NaHCO₃ $rightwards arrow$ Na₂CO₃ + CO₂ + H₂O
1 mole of CO₂ is evolved from 2 moles of sodium bicarbonate.
2 moles(168g) of sodium bicarbonate is equivalent to 22.4L of carbon dioxide at STP.
0.56L of carbon dioxide gas as STP gives 4,3gm of sodium bicarbonate.

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