Chemistry-
General
Easy

Question

The correct statement about the following disaccharide is:
I)
II)

  1. ring (I) is pyranose with alpha-glycosidic link    
  2. ring (I) is furanose with alpha -glycosidic link    
  3. ring (II) is furanose with alpha -glycosidic link    
  4. ring (II) is pyranose with beta minusglycosidic link    

The correct answer is: ring (I) is pyranose with alpha-glycosidic link

Related Questions to study

General
Chemistry-

A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.
table row cell P fraction numerator 1. M e M g B r over denominator 2. H to the power of plus end exponent comma H subscript 2 end subscript O end fraction Q fraction numerator 1. O subscript 3 end subscript over denominator 2. Z n comma H subscript 2 end subscript O end fraction R fraction numerator 1. O H to the power of minus end exponent over denominator 2. capital delta end fraction S end cell row cell 3. H subscript 2 end subscript S O subscript 4 end subscript comma capital delta end cell end table
The structures of the products Q and R, respectively, are:

A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.
table row cell P fraction numerator 1. M e M g B r over denominator 2. H to the power of plus end exponent comma H subscript 2 end subscript O end fraction Q fraction numerator 1. O subscript 3 end subscript over denominator 2. Z n comma H subscript 2 end subscript O end fraction R fraction numerator 1. O H to the power of minus end exponent over denominator 2. capital delta end fraction S end cell row cell 3. H subscript 2 end subscript S O subscript 4 end subscript comma capital delta end cell end table
The structures of the products Q and R, respectively, are:

Chemistry-General
General
Chemistry-

Consider the following reactions I and II,
I)
II)
Products 'X' and 'Y' are respectively:

Consider the following reactions I and II,
I)
II)
Products 'X' and 'Y' are respectively:

Chemistry-General
General
Chemistry-

In which of the following cases, the nitration will take place at meta-position?
I)
II)
III)
IV)

In which of the following cases, the nitration will take place at meta-position?
I)
II)
III)
IV)

Chemistry-General
parallel
General
Chemistry-

The correct order of decreasing basicity of the following compounds is:
I)
II)
III)
IV)

The correct order of decreasing basicity of the following compounds is:
I)
II)
III)
IV)

Chemistry-General
General
Chemistry-

Phenol . gives two polymers on condensation with formaldehyde:

X and Y are :

Phenol . gives two polymers on condensation with formaldehyde:

X and Y are :

Chemistry-General
General
Chemistry-

X and Yare:

X and Yare:

Chemistry-General
parallel
General
Chemistry-

Chemistry-General
General
Maths-

Simplify : 2m-3 =17

Simplify : 2m-3 =17

Maths-General
General
Physics-

In the figure is shown Young’s double slit experiment. Q is the position of the first bright fringe on the right side of O. P is the 11th fringe on the other side, as measured from Q. If the wavelength of the light used is 6000 cross times 1 0 to the power of negative 10 end exponent m, then S subscript 1 end subscript B will be equal to

In the figure is shown Young’s double slit experiment. Q is the position of the first bright fringe on the right side of O. P is the 11th fringe on the other side, as measured from Q. If the wavelength of the light used is 6000 cross times 1 0 to the power of negative 10 end exponent m, then S subscript 1 end subscript B will be equal to

Physics-General
parallel
General
Physics-

When one of the slits of Young’s experiment is covered with a transparent sheet of thickness 4.8 mm, the central fringe shifts to a position originally occupied by the 30th bright fringe. What should be the thickness of the sheet if the central fringe has to shift to the position occupied by 20th bright fringe

When one of the slits of Young’s experiment is covered with a transparent sheet of thickness 4.8 mm, the central fringe shifts to a position originally occupied by the 30th bright fringe. What should be the thickness of the sheet if the central fringe has to shift to the position occupied by 20th bright fringe

Physics-General
General
Physics-

Figure here shows P and Q as two equally intense coherent sources emitting radiations of wavelength 20 m. The separation PQ is 5.0 m and phase of P is ahead of the phase of Q by 90o. A, B and C are three distant points of observation equidistant from the mid-point of PQ. The intensity of radiations at A, B, C will bear the ratio

Figure here shows P and Q as two equally intense coherent sources emitting radiations of wavelength 20 m. The separation PQ is 5.0 m and phase of P is ahead of the phase of Q by 90o. A, B and C are three distant points of observation equidistant from the mid-point of PQ. The intensity of radiations at A, B, C will bear the ratio

Physics-General
General
Maths-

Represent -7 + 3 on number line

When we add something to the given number, we don’t start counting the second number from zero. We count the places from the number itself. Any negative value means we move in left direction. Any positive value means we move in right direction.

Represent -7 + 3 on number line

Maths-General

When we add something to the given number, we don’t start counting the second number from zero. We count the places from the number itself. Any negative value means we move in left direction. Any positive value means we move in right direction.

parallel
General
Maths-

Statement-I: integral subscript blank superscript blank fraction numerator 1 over denominator 4 plus 5 s i n x end fraction d x equals 1 third l o g vertical line fraction numerator 2 t a n left parenthesis x divided by 2 right parenthesis plus 1 over denominator 2 t a n left parenthesis x divided by 2 right parenthesis plus 4 end fraction vertical line plus c
Statement-II: If 0<a<b, then integral subscript blank superscript blank fraction numerator d x over denominator a plus b s i n x end fraction equals fraction numerator 1 over denominator square root of b squared minus a squared end root end fraction l o g vertical line fraction numerator a t a n left parenthesis x divided by 2 right parenthesis plus b minus square root of b squared minus a squared end root over denominator a t a n left parenthesis x divided by 2 right parenthesis plus b plus square root of b squared minus a squared end root end fraction vertical line plus c

Statement-I: integral subscript blank superscript blank fraction numerator 1 over denominator 4 plus 5 s i n x end fraction d x equals 1 third l o g vertical line fraction numerator 2 t a n left parenthesis x divided by 2 right parenthesis plus 1 over denominator 2 t a n left parenthesis x divided by 2 right parenthesis plus 4 end fraction vertical line plus c
Statement-II: If 0<a<b, then integral subscript blank superscript blank fraction numerator d x over denominator a plus b s i n x end fraction equals fraction numerator 1 over denominator square root of b squared minus a squared end root end fraction l o g vertical line fraction numerator a t a n left parenthesis x divided by 2 right parenthesis plus b minus square root of b squared minus a squared end root over denominator a t a n left parenthesis x divided by 2 right parenthesis plus b plus square root of b squared minus a squared end root end fraction vertical line plus c

Maths-General
General
Maths-

Statement-I: integral subscript blank superscript blank fraction numerator 1 over denominator 5 plus 4 c o s x end fraction d x equals 2 over 3 t a n to the power of negative 1 end exponent left parenthesis fraction numerator 4 plus 5 t a n left parenthesis x divided by 2 right parenthesis over denominator 3 end fraction right parenthesis plus c
Statement-II: If a>0, a>b, then integral subscript blank superscript blank fraction numerator d x over denominator a plus b s i n x end fraction equals fraction numerator 2 over denominator square root of a squared minus b squared end root end fraction t a n to the power of negative 1 end exponent left parenthesis fraction numerator b plus a t a n left parenthesis x divided by 2 right parenthesis over denominator square root of a squared minus b squared end root end fraction right parenthesis plus c

Statement-I: integral subscript blank superscript blank fraction numerator 1 over denominator 5 plus 4 c o s x end fraction d x equals 2 over 3 t a n to the power of negative 1 end exponent left parenthesis fraction numerator 4 plus 5 t a n left parenthesis x divided by 2 right parenthesis over denominator 3 end fraction right parenthesis plus c
Statement-II: If a>0, a>b, then integral subscript blank superscript blank fraction numerator d x over denominator a plus b s i n x end fraction equals fraction numerator 2 over denominator square root of a squared minus b squared end root end fraction t a n to the power of negative 1 end exponent left parenthesis fraction numerator b plus a t a n left parenthesis x divided by 2 right parenthesis over denominator square root of a squared minus b squared end root end fraction right parenthesis plus c

Maths-General
General
Maths-

Statement-I: integral subscript blank superscript blank fraction numerator 1 over denominator 3 plus 2 c o s x end fraction d x equals fraction numerator 2 over denominator square root of 5 end fraction t a n to the power of negative 1 end exponent left parenthesis fraction numerator 1 over denominator square root of 5 end fraction t a n x over 2 right parenthesis plus c
Statement-II: If a>b then integral subscript blank superscript blank fraction numerator d x over denominator a plus b c o s x end fraction equals fraction numerator 2 over denominator square root of a squared minus b squared end root end fraction t a n to the power of negative 1 end exponent left parenthesis square root of fraction numerator a minus b over denominator a plus b end fraction end root t a n x over 2 right parenthesis plus c

Statement-I: integral subscript blank superscript blank fraction numerator 1 over denominator 3 plus 2 c o s x end fraction d x equals fraction numerator 2 over denominator square root of 5 end fraction t a n to the power of negative 1 end exponent left parenthesis fraction numerator 1 over denominator square root of 5 end fraction t a n x over 2 right parenthesis plus c
Statement-II: If a>b then integral subscript blank superscript blank fraction numerator d x over denominator a plus b c o s x end fraction equals fraction numerator 2 over denominator square root of a squared minus b squared end root end fraction t a n to the power of negative 1 end exponent left parenthesis square root of fraction numerator a minus b over denominator a plus b end fraction end root t a n x over 2 right parenthesis plus c

Maths-General
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