Chemistry
Grade-9
Easy
Question
The volume occupied at 0oC and 2 atm pressure by the gas evolved from dry ice (density of dry ice 1.1gm/ml)of the volume of 8cc is:
- 22.4L
- 2.24L
- 0.224L
- 224L
Hint:
Gas law is PV= nRT
The correct answer is: 2.24L
The correct option is b)2.24L.
Given:
Temperature = 0 degree = 273 K
R = 0.0821 L atm/K-mol;
Pressure = 2 atm
Volume of dry ice = 8 cc = 8 ml
Density = 1.1 g/ml
Mass = density x volume =
1.1 × 8 = 8.8 gAccording to gas law,
PV=nRT
Molecular weight of dry ice (CO2) = 44 g/mol
n= given weight/ molecular weight
n= 8.8 / 44
n=0.2
1.1 × 8 = 8.8 g
According to gas law,PV=nRT
Molecular weight of dry ice (CO2) = 44 g/mol
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