English-2
Grade-8
Easy

Question

Fill in the blanks with suitable conjunctions.
I ran fast ______ I was already late for the class.
.

  1. Yet
  2. As
  3. Than
  4. None of the above

hintHint:

Conjunctions are part of speech that connect two or more words, phrases, clauses or sentences. Conjunctions are also called joining words. Example- both, nor, also etc.

The correct answer is: As


    Solution : (a) Yet
    I ran fast as  I was already late for the class.
    "As" is a "Coordinating conjunction" word. These words  join words, phrases and clauses that are coordinate or are equal to each other. Here, "I ran fast"  becaue "I was already late for the class" both have equal importance.

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    Radius of the data = 156 cm
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    Since, we have derived an expression for volume of the cone as  1 third πr squared straight h. Then, calculate the volume of the cone using the given data.
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    Height of the cone = 1.6 meters
    Hence, Volume of the cone = 1 third πr squared straight h
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    parallel
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    Height of a cone = 4 inches
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    parallel
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    A cone has the radius of 10 inches and the height of 9 inches. Find the volume of the cone. Round your answer to the nearest tenth.

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    Height of a cone :   9 inches
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    Since, we have derived an expression for volume of a cone as 1 third πr squared straight h . Hence, calculate any attribute of a structure using the given data.
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    A cone has the radius of 6 inches and the height of 5 inches. Find the volume of the cone. Round your answer to the nearest tenth.

    Since, we have derived an expression for volume of a cone as 1 third straight pir2h. Hence, just substitute values of a given attributes to find the volume of a cone.
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                      Radius of base of a cone = 6 inches
                       Height of base of a cone = 5 inches
    Hence, Volume of a cone = 1 third straight pir2h
                                             =fraction numerator 3.14 cross times 6 cross times 6 cross times 5 over denominator 3 end fraction
                                             =188.49 inches3.
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    A cone has the radius of 6 inches and the height of 5 inches. Find the volume of the cone. Round your answer to the nearest tenth.

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    Since, we have derived an expression for volume of a cone as 1 third straight pir2h. Hence, just substitute values of a given attributes to find the volume of a cone.
    Given that:
                      Radius of base of a cone = 6 inches
                       Height of base of a cone = 5 inches
    Hence, Volume of a cone = 1 third straight pir2h
                                             =fraction numerator 3.14 cross times 6 cross times 6 cross times 5 over denominator 3 end fraction
                                             =188.49 inches3.
    ***Volume of a cone is 188.49 cubic inches.

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    Find the volume of corn held in this cone-shaped grain silo. Use 3.14 for π and round to the nearest cubic foot.

    Since, we have derived an expression for volume of a cone as  1 third πr to the power of 2 to the power of blank end exponentsquare root of l squared space minus space r squared end root. hence, substituting the values of radius and slant height values we can obtain volume of a cone easily.

    Given that:
    Slant height of a cone (l) = 10 feet
    Radius of a cone (r) = 5 feet
    Hence, volume of a cone is =   1 third πr to the power of 2 to the power of blank end exponentsquare root of l squared space minus space r squared end root
    =fraction numerator 3.14 cross times 6 cross times 6 cross times square root of 100 minus 36 end root over denominator 3 end fraction
    =fraction numerator 3.14 cross times 6 cross times 6 cross times 8 over denominator 3 end fraction
    = 301.44 feet3.
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    Find the volume of corn held in this cone-shaped grain silo. Use 3.14 for π and round to the nearest cubic foot.

    MathematicsGrade-8

    Since, we have derived an expression for volume of a cone as  1 third πr to the power of 2 to the power of blank end exponentsquare root of l squared space minus space r squared end root. hence, substituting the values of radius and slant height values we can obtain volume of a cone easily.

    Given that:
    Slant height of a cone (l) = 10 feet
    Radius of a cone (r) = 5 feet
    Hence, volume of a cone is =   1 third πr to the power of 2 to the power of blank end exponentsquare root of l squared space minus space r squared end root
    =fraction numerator 3.14 cross times 6 cross times 6 cross times square root of 100 minus 36 end root over denominator 3 end fraction
    =fraction numerator 3.14 cross times 6 cross times 6 cross times 8 over denominator 3 end fraction
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    parallel

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