Mathematics
Grade5
Easy

Question

open parentheses 1 over 7 plus 1 half close parentheses cross times 1 7 over 2

  1. 56 over 5
  2. 1
  3. 2
  4. None of the above

hintHint:

first add the terms inside the bracket and then multiply

The correct answer is: None of the above


    1 over 7 plus 1 half equals fraction numerator 2 cross times 1 plus 1 cross times 7 over denominator 14 end fraction equals 9 over 14
1 7 over 2 equals fraction numerator 2 cross times 1 plus 7 over denominator 2 end fraction equals 9 over 2
9 over 2 cross times 9 over 14 equals 81 over 28

    Follow the BODMAS rule. So, first let’s add 1/7 and 1/3, we get 9/14. Now , convert the mixed fraction into improper fraction, we get 9/2. Multiplying 9/14 x 9/2 , we get 81/28. This isn’t given in any of the options, so, answer is none of the above.

    Related Questions to study

    Grade5
    Mathematics

    2 over 15 cross times 1 1 half

    Let’s convert the mixed fractions into improper fractions. We get 2/15 and ((2 x 1) + 1)/2, i.e., 2/15 and 3/2. Let’s calculate the product 2/15 x 3/2 we get 1/5

    2 over 15 cross times 1 1 half

    MathematicsGrade5

    Let’s convert the mixed fractions into improper fractions. We get 2/15 and ((2 x 1) + 1)/2, i.e., 2/15 and 3/2. Let’s calculate the product 2/15 x 3/2 we get 1/5

    Grade5
    Mathematics

    Compare using >, <, or =
    17 8 over 7 space box enclose blank end enclose space 17.

    Compare using >, <, or =
    17 8 over 7 space box enclose blank end enclose space 17.

    MathematicsGrade5
    Grade5
    Mathematics

    2 over 2 cross times 1 1 third

    Let’s convert the mixed fractions into improper fractions. We get 2/2 and ((3 x 1) + 1)/3, i.e., 2/2 and 4/3. Let’s calculate the product 2/2  x 4/3 we get 4/3

    2 over 2 cross times 1 1 third

    MathematicsGrade5

    Let’s convert the mixed fractions into improper fractions. We get 2/2 and ((3 x 1) + 1)/3, i.e., 2/2 and 4/3. Let’s calculate the product 2/2  x 4/3 we get 4/3

    parallel
    Grade5
    Mathematics

    1 1 over 20 cross times 1 over 7

    Let’s convert the mixed fractions into improper fractions. We get ((20 x 1) +1)/20 and 1/7 i.e., 21/20 and 1/7. Let’s calculate the product 21/20 x 1/7 we get 3/20

    1 1 over 20 cross times 1 over 7

    MathematicsGrade5

    Let’s convert the mixed fractions into improper fractions. We get ((20 x 1) +1)/20 and 1/7 i.e., 21/20 and 1/7. Let’s calculate the product 21/20 x 1/7 we get 3/20

    Grade5
    Mathematics

    1 22 over 123 cross times 143 over 20 cross times 0

    Anything multiplied by 0 is 0. Hence, the answer is 0.

    1 22 over 123 cross times 143 over 20 cross times 0

    MathematicsGrade5

    Anything multiplied by 0 is 0. Hence, the answer is 0.

    Grade5
    Mathematics

    3 1 fifth cross times 10 over 2

    Let’s convert the mixed fractions into improper fractions. We get ((5 x 3) +1)/5 and 10/2, i.e., 16/5 and 10/2. Let’s calculate the product 16/5 x 10/5 we get 16

    3 1 fifth cross times 10 over 2

    MathematicsGrade5

    Let’s convert the mixed fractions into improper fractions. We get ((5 x 3) +1)/5 and 10/2, i.e., 16/5 and 10/2. Let’s calculate the product 16/5 x 10/5 we get 16

    parallel
    Grade5
    Mathematics

    1 1 over 9 cross times 2 1 third

    Lets convert the mixed fractions into improper fractions. We get ((9 x 1) +1)/9 and ((3 x 2)+ 1)/3, i.e., 10/9 and7/3. Let’s calculate the product 10/9 x 7/3 we get 70/27

    1 1 over 9 cross times 2 1 third

    MathematicsGrade5

    Lets convert the mixed fractions into improper fractions. We get ((9 x 1) +1)/9 and ((3 x 2)+ 1)/3, i.e., 10/9 and7/3. Let’s calculate the product 10/9 x 7/3 we get 70/27

    Grade5
    Mathematics

    4 1 half cross times 1 half

    Lets convert the mixed fractions into improper fractions. We get ((2 x 4) +1)/2 and 1/2 i.e., 9/2 and 1/2. Let’s calculate the product 9/2 x 1/2 we get 9/4

    4 1 half cross times 1 half

    MathematicsGrade5

    Lets convert the mixed fractions into improper fractions. We get ((2 x 4) +1)/2 and 1/2 i.e., 9/2 and 1/2. Let’s calculate the product 9/2 x 1/2 we get 9/4

    Grade5
    Mathematics

    3 3 over 9 cross times 1 1 third

    Lets convert the mixed fractions into improper fractions. We get ((9 x 3) +3)/9 and ((3 x 1)+ 1)/3, i.e., 30/9 and 4/3. Let’s calculate the product 30/9 x 4/3 . we get 40/9

    3 3 over 9 cross times 1 1 third

    MathematicsGrade5

    Lets convert the mixed fractions into improper fractions. We get ((9 x 3) +3)/9 and ((3 x 1)+ 1)/3, i.e., 30/9 and 4/3. Let’s calculate the product 30/9 x 4/3 . we get 40/9

    parallel
    Grade5
    Mathematics

    Mark has a rectangular doormat on her porch. The mat is 4 over 5 m long and1 half  m wide. What is the area of   the doormat?

    Given, length = 4/5 m and breath =1/2 m. Let’s find out the product of the 2 dimensions given. We get 1/2 x 4/5 = 2/5 sq. m, which is the required answer.

    Mark has a rectangular doormat on her porch. The mat is 4 over 5 m long and1 half  m wide. What is the area of   the doormat?

    MathematicsGrade5

    Given, length = 4/5 m and breath =1/2 m. Let’s find out the product of the 2 dimensions given. We get 1/2 x 4/5 = 2/5 sq. m, which is the required answer.

    Grade5
    Mathematics

    Steven calculated the area of a square to be 1 over 81 square yard. What is the side length of the square?


    Given, area of square = 1/81 sq yard. This means that the square of side length is 1/ 81. This means that we need to find the square root of 1/ 81. Square root of 1 is 1.  To find the square root of 81, let’s find the factors of 81.  By using hit and trial method, we can write that 81 = 3 x 3 x 3 x3 = 9 x 9. Hence, 9 is the square root of 81. Hence, our required answer is 1/9 , which is the square root of 1/81.

    Steven calculated the area of a square to be 1 over 81 square yard. What is the side length of the square?


    MathematicsGrade5

    Given, area of square = 1/81 sq yard. This means that the square of side length is 1/ 81. This means that we need to find the square root of 1/ 81. Square root of 1 is 1.  To find the square root of 81, let’s find the factors of 81.  By using hit and trial method, we can write that 81 = 3 x 3 x 3 x3 = 9 x 9. Hence, 9 is the square root of 81. Hence, our required answer is 1/9 , which is the square root of 1/81.

    Grade5
    Mathematics

    If Andrew makes 6 sandwiches with an 9.3 ounces of peanut butter on each, how much peanut butter does she put on all the sandwiches?

    Number of sandwiches = 6
    Amount of peanut butter on 1 sandwich = 9.3 ounces
    Total amount of butter = 9.3 x 6 = 55.8 ounces

    If Andrew makes 6 sandwiches with an 9.3 ounces of peanut butter on each, how much peanut butter does she put on all the sandwiches?

    MathematicsGrade5

    Number of sandwiches = 6
    Amount of peanut butter on 1 sandwich = 9.3 ounces
    Total amount of butter = 9.3 x 6 = 55.8 ounces

    parallel
    Grade5
    Mathematics

    Irene buys a talking doll for $11.66 and batteries for $3.22. She pays with a $30 bill. Estimate how much change she should get ?

    Cost of doll=$ 11.66
    Cost of batteries =$ 3.22
    Total cost = 11.66 + 3.22 =$ 14.88
    Amount paid = $ 30
    Amount to be returned = $ 30- total cost= $30 - $ 14.88= $ 15.12$

    Irene buys a talking doll for $11.66 and batteries for $3.22. She pays with a $30 bill. Estimate how much change she should get ?

    MathematicsGrade5

    Cost of doll=$ 11.66
    Cost of batteries =$ 3.22
    Total cost = 11.66 + 3.22 =$ 14.88
    Amount paid = $ 30
    Amount to be returned = $ 30- total cost= $30 - $ 14.88= $ 15.12$

    Grade5
    Mathematics

    Each person on a Ferris wheel pays $7.50 for a ticket. There are 82 passengers. How much money is collected from all the passengers?

    Each person on a Ferris wheel pays $7.50 for a ticket. There are 82 passengers. How much money is collected from all the passengers?

    MathematicsGrade5
    Grade5
    Mathematics

    Find the area of a rectangle with side lengths 5 over 2 centimeters and 2 over 15 centimeters.?

    Find the area of a rectangle with side lengths 5 over 2 centimeters and 2 over 15 centimeters.?

    MathematicsGrade5
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.