Mathematics
Grade6
Easy

Question

3 over 7 cross times 7 over 3 =

  1. 21 over 3
  2. 21 over 20
  3. 7 over 21
  4. 1

Hint:

In fraction multiplication, first we multiply the numerators of the given numbers. This product becomes the numerator of the product. Then we multiply the denominators of the given numbers, which becomes the denominator of the product. Thus, we get a product. Now, in this question we will not get the product in the simplest form so we need to reduce it to the simplest form. To reduce it we need to divide both the numerator and the denominator by the HCF [highest common factor] of both the numbers.

The correct answer is: 1


Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 3 over 7 cross times 7 over 3 equals 21 over 21
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 21 in this question.
Hence, we get 21 over 21 equals 1
Thus, the correct option is option (d)

In the question, another approach could be that we can cut both the threes and the sevens, i.e., 3 in the numerator of the first fraction and the 3 in the denominator of the second fraction and 7 in the denominator of the first fraction and 7 in the numerator of the second fraction.. That way we do not have to reduce the fraction later into its simplest form.
Hence, 3 over 7 cross times 7 over 3 equals 1
Thus, we get option (d) as the correct option.

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