Mathematics
Grade10
Easy

Question

A commercial jet flies 1500 miles with the wind. In the same amount of time, it can fly 1000 miles against the wind. The speed of the jet in still air is 550 mph. Write a rational equation to find the speed of the wind.

  1. 25w2 – 1000 = 0
  2. 5w – 550 = 0
  3. w2 – 1000 = 0
  4. 6w2 – 10w + 500 = 0

hintHint:

A rational expression is an expression of the form where Pand Q are nonzero polynomials.

The correct answer is: 5w – 550 = 0


    Step 1 of 1:
    We have given a commercial jet flies 1500 miles with the wind. In the same amount of time, it can fly 1000 miles against the wind. The speed of the jet in still air is 550 mph.
    Let w be the speed of the wind
    Speed with wind = 550 + w
    Speed against wind = 550 - w
    fraction numerator 1500 over denominator 550 plus omega end fraction equals fraction numerator 1000 over denominator 550 minus omega end fraction
    rightwards double arrow 3 left parenthesis 550 minus omega right parenthesis equals 2 left parenthesis 550 plus omega right parenthesis
    rightwards double arrow 550 cross times 3 minus 3 omega equals 2 cross times 550 plus 2 omega
    rightwards double arrow space 5 space w minus 550 equals 0

    We know that Speed=Distance/Time

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