Mathematics

Grade10

Easy

Question

# A man starts his job with a certain monthly salary and a fixed increment every year. If his salary will be Rs. 11000 after 2 years and Rs. 14000 after 4 years of his service. Find his starting salary and his annual increment.

- Starting salary is Rs. 7500 and increment is Rs. 2500
- Starting salary is Rs.5000 and increment is Rs. 1800
- Starting salary is Rs. 8000 and increment is Rs. 1500
- Starting salary is Rs. 7000 and increment is Rs. 1300

Hint:

### In this question, A man start job with salary and fixed increment, if his salary will be Rs. 11000 after 2 years and Rs 14000 after 4years. We have to find his starting salary and annual increment. Let these two as a variable and write the equation for it.

## The correct answer is: Starting salary is Rs. 8000 and increment is Rs. 1500

### Here we have to find a man starting salary and annual salary.

Firstly , Let salary be x and increment every year be y.

His salary will be Rs 11000 after 2 year, so we can write,

x + 2y = 11000 --(1)

and Rs 14000 after 4 years, we can write;

x + 4y = 14000 --- (2)

using elimination method,

Subtract eq(1) from eq(2) , we get;

x + 4y = 14000

x + 2y = 11000

--------------------------

0 + 2y = 3000

y = 1500

substitute y = 1500 in eq(1), we get,

x + 2 x 1500 = 11000

x + 3000 = 11000

x = 11000 – 3000

x = 8000

Therefore, Starting salary is Rs 8000 and increment is Rs. 1500.

or,

Let starting salary = x

Increment every year = y

x +2y = 11,000 ....... eq(1)

x + 4y = 14,000 ......eq(2)

Substract eq(1) from eq(2)

2y = 3,000y = 1500

Substitute y= 1500 in eq(1), we get x = 11,000 − 3,000

x = 8,000

starting salary = 8,000

Increment = 1500

In this question, we have to find his starting salary and annual increment. Let be consider both of them as a variable and make two or more equation as per given information and solve these equation.