Mathematics
Easy

Question

# A man starts his job with a certain monthly salary and a fixed increment every year. If his salary will be Rs. 11000 after 2 years and Rs. 14000 after 4 years of his service. Find his starting salary and his annual increment.

## Starting salary is Rs. 7500 and increment is Rs. 2500Starting salary is Rs.5000 and increment is Rs. 1800Starting salary is Rs. 8000 and increment is Rs. 1500 Starting salary is Rs. 7000 and increment is Rs. 1300 Hint:

## The correct answer is: Starting salary is Rs. 8000 and increment is Rs. 1500

### Here we have to find a man starting salary and annual salary.Firstly , Let salary be x and increment every year be y.His salary will be Rs 11000 after 2 year, so we can write,x + 2y = 11000 --(1)and Rs 14000 after 4 years, we can write;x + 4y = 14000 --- (2)using elimination method,Subtract eq(1) from eq(2) , we get;  x + 4y = 14000  x + 2y = 11000-------------------------- 0 + 2y = 3000y = 1500substitute y = 1500 in eq(1), we get,x + 2 x 1500 = 11000x + 3000 = 11000x = 11000 – 3000x = 8000Therefore, Starting salary is Rs 8000 and increment is Rs. 1500.or,Let starting salary = xIncrement every year = yx +2y = 11,000                 ....... eq(1)x + 4y = 14,000                     ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500Substitute y= 1500  in eq(1), we get x = 11,000 − 3,000x = 8,000starting salary = 8,000Increment  = 1500

In this question, we have to find his starting salary and annual increment. Let be consider both of them as a variable and make two or more equation as per given information and solve these equation.

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