A man starts his job with a certain monthly salary and a fixed increment every year. If his salary will be Rs. 11000 after 2 years and Rs. 14000 after 4 years of his service. Find his starting salary and his annual increment.

The correct answer is: Starting salary is Rs. 8000 and increment is Rs. 1500 

Here we have to find a man starting salary and annual salary.
Firstly , Let salary be x and increment every year be y.
His salary will be Rs 11000 after 2 year, so we can write,
x + 2y = 11000 --(1)
and Rs 14000 after 4 years, we can write;
x + 4y = 14000 --- (2)
using elimination method,
Subtract eq(1) from eq(2) , we get;
  x + 4y = 14000
  x + 2y = 11000
--------------------------
0 + 2y = 3000
y = 1500
substitute y = 1500 in eq(1), we get,
x + 2 x 1500 = 11000
x + 3000 = 11000
x = 11000 – 3000
x = 8000
Therefore, Starting salary is Rs 8000 and increment is Rs. 1500.
or,
Let starting salary = x
Increment every year = y
x +2y = 11,000                 ....... eq(1)
x + 4y = 14,000                     ......eq(2)
Substract eq(1) from eq(2)
2y = 3,000y = 1500
Substitute y= 1500  in eq(1), we get x = 11,000 − 3,000
x = 8,000
starting salary = 8,000
Increment  = 1500

In this question, we have to find his starting salary and annual increment. Let be consider both of them as a variable and make two or more equation as per given information and solve these equation.