Mathematics
Grade10
Easy

Question

A man starts his job with a certain monthly salary and a fixed increment every year. If his salary will be Rs. 11000 after 2 years and Rs. 14000 after 4 years of his service. Find his starting salary and his annual increment.

  1. Starting salary is Rs. 7500 and increment is Rs. 2500
  2. Starting salary is Rs.5000 and increment is Rs. 1800
  3. Starting salary is Rs. 8000 and increment is Rs. 1500 
  4. Starting salary is Rs. 7000 and increment is Rs. 1300

Hint:

In this question, A man start job with salary and fixed increment, if his salary will be Rs. 11000 after 2 years and Rs 14000 after 4years. We have to find his starting salary and annual increment. Let these two as a variable and write the equation for it.

The correct answer is: Starting salary is Rs. 8000 and increment is Rs. 1500 


    Here we have to find a man starting salary and annual salary.
    Firstly , Let salary be x and increment every year be y.
    His salary will be Rs 11000 after 2 year, so we can write,
    x + 2y = 11000 --(1)
    and Rs 14000 after 4 years, we can write;
    x + 4y = 14000 --- (2)
    using elimination method,
    Subtract eq(1) from eq(2) , we get;
      x + 4y = 14000
      x + 2y = 11000
    --------------------------
    0 + 2y = 3000
    y = 1500
    substitute y = 1500 in eq(1), we get,
    x + 2 x 1500 = 11000
    x + 3000 = 11000
    x = 11000 – 3000
    x = 8000
    Therefore, Starting salary is Rs 8000 and increment is Rs. 1500.
    or,
    Let starting salary = x
    Increment every year = y
    x +2y = 11,000                 ....... eq(1)
    x + 4y = 14,000                     ......eq(2)
    Substract eq(1) from eq(2)
    2y = 3,000y = 1500
    Substitute y= 1500  in eq(1), we get x = 11,000 − 3,000
    x = 8,000
    starting salary = 8,000
    Increment  = 1500

    In this question, we have to find his starting salary and annual increment. Let be consider both of them as a variable and make two or more equation as per given information and solve these equation.

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