Mathematics
Easy

Question

# A man starts his job with a certain monthly salary and a fixed increment every year. If his salary will be Rs. 11000 after 2 years and Rs. 14000 after 4 years of his service. Find his starting salary and his annual increment.

Hint:

## The correct answer is: Starting salary is Rs. 8000 and increment is Rs. 1500

### Here we have to find a man starting salary and annual salary.Firstly , Let salary be x and increment every year be y.His salary will be Rs 11000 after 2 year, so we can write,x + 2y = 11000 --(1)and Rs 14000 after 4 years, we can write;x + 4y = 14000 --- (2)using elimination method,Subtract eq(1) from eq(2) , we get;  x + 4y = 14000  x + 2y = 11000-------------------------- 0 + 2y = 3000y = 1500substitute y = 1500 in eq(1), we get,x + 2 x 1500 = 11000x + 3000 = 11000x = 11000 – 3000x = 8000Therefore, Starting salary is Rs 8000 and increment is Rs. 1500.or,Let starting salary = xIncrement every year = yx +2y = 11,000                 ....... eq(1)x + 4y = 14,000                     ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500Substitute y= 1500  in eq(1), we get x = 11,000 − 3,000x = 8,000starting salary = 8,000Increment  = 1500

In this question, we have to find his starting salary and annual increment. Let be consider both of them as a variable and make two or more equation as per given information and solve these equation.