Solution for the question - a rectangular sheet of paper is 15(3)/(4) cm long having perimeter56(1)/(2) cm, then find the its width. 14(1)/(2) '/> 12(1)/(4) '/>

Mathematics

Grade6

Easy

Question

A rectangular sheet of paper is $15 fraction numerator 3 over denominator 4 end fraction$ cm long having perimeter $56 fraction numerator 1 over denominator 2 end fraction$ cm, then find the its width.

$11 \frac{1}{2}$
$12 \frac{1}{2}$
$12 \frac{1}{4}$
$14 \frac{1}{2}$

hint Hint:

To find the width of the rectangle when perimeter and length is given use the formula ,
Perimeter = 2( length +breadth ) and substitute the given values and find the Width of the rectangular sheet.

The correct answer is: $12 fraction numerator 1 over denominator 2 end fraction$

Length of a rectangular sheet $equals 15 fraction numerator 3 over denominator 4 end fraction c m$
The perimeter of the sheet $equals 56 fraction numerator 1 over denominator 2 end fraction$ cm
Let the width of the sheet be x cm.
Then $2 open parentheses 15 fraction numerator 3 over denominator 4 end fraction plus x close parentheses equals 56 fraction numerator 1 over denominator 2 end fraction$
Converting into improper fraction to simplify the equation.
Improper fraction = $fraction numerator open parentheses text Whole number × Denominator end text close parentheses text + Numerator end text over denominator text Denominator end text end fraction$
$rightwards double arrow 15 fraction numerator 3 over denominator 4 end fraction plus x equals fraction numerator 56 fraction numerator 1 over denominator 2 end fraction over denominator 2 end fraction equals fraction numerator 113 over denominator 4 end fraction$
$therefore x equals fraction numerator 113 over denominator 4 end fraction minus 15 fraction numerator 3 over denominator 4 end fraction equals fraction numerator 113 over denominator 4 end fraction minus fraction numerator 63 over denominator 4 end fraction equals fraction numerator 25 over denominator 2 end fraction equals 12 fraction numerator 1 over denominator 2 end fraction c m$
$therefore$ Width of the sheet $equals 12 fraction numerator 1 over denominator 2 end fraction c m$

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A rectangular sheet of paper is $15 fraction numerator 3 over denominator 4 end fraction$ cm long having perimeter $56 fraction numerator 1 over denominator 2 end fraction$ cm, then find the its width.

$11 \frac{1}{2}$
$12 \frac{1}{2}$
$12 \frac{1}{4}$
$14 \frac{1}{2}$

To find the width of the rectangle when perimeter and length is given use the formula ,
Perimeter = 2( length +breadth ) and substitute the given values and find the Width of the rectangular sheet.

The correct answer is: $12 fraction numerator 1 over denominator 2 end fraction$

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Can’t find what you’re looking for?

A rectangular sheet of paper is cm long having perimeter cm, then find the its width.

To find the width of the rectangle when perimeter and length is given use the formula ,Perimeter = 2( length +breadth ) and substitute the given values and find the Width of the rectangular sheet.

The correct answer is:

Length of a rectangular sheet The perimeter of the sheet cmLet the width of the sheet be x cm.Then Converting into improper fraction to simplify the equation.Improper fraction = Width of the sheet

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With Turito Foundation.

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A rectangular sheet of paper is $15 fraction numerator 3 over denominator 4 end fraction$ cm long having perimeter $56 fraction numerator 1 over denominator 2 end fraction$ cm, then find the its width.

To find the width of the rectangle when perimeter and length is given use the formula ,
Perimeter = 2( length +breadth ) and substitute the given values and find the Width of the rectangular sheet.

The correct answer is: $12 fraction numerator 1 over denominator 2 end fraction$