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Mathematics

Grade5

Easy

Question

Add $1 third$ and $1 over 6$ .

$\frac{2}{1}$
$\frac{4}{8}$
$\frac{1}{2}$
$\frac{2}{9}$

hint Hint:

In this question we have to add two fractions for that we have to make denominator same this can be done by taking LCM. LCM is the least common multiple of two integers. We will use the prime factorization method to find the LCM. In prime factorization method the simply put the factor of each number and then for LCM we take product of factors, but we consider the repeated factors only one time with the highest exponent.

The correct answer is: $1 half$

$1 third space equals space 2 over 6 space left parenthesis Multiply space with space 2 right parenthesis space 2 over 6 space plus space 1 over 6 equals space 3 over 6 equals 1 half$
Step1: First we will write all the prime factors of the denominators
In this question the denominators are $3$ and $6$ .
Factors of $3$ are: $3$
Factors of $6$ are: $3 cross times 2$
Step2: For calculating the LCM we will multiply the factors by considering the common factors only one time with the highest exponent.
In this case the factor $3$ is common in both $3$ and $6$ so we will multiply it only once with the highest exponent.
LCM( $3 comma 6$ ) = $3 cross times 2$ .
LCM( $3 comma 6$ ) = $6$
Step3: Now what we do is divide the LCM by each denominator and multiply the numerator by quotient and then add them
So, $6 over 3 space equals space 2$
and $6 over 6 space equals space 1$
So, we will multiply the numerator of $3$ by $2$ and numerator of $6$ by $1$ .
$fraction numerator 1 cross times 2 space plus space 1 cross times 1 over denominator 6 end fraction space equals 3 over 6$
So, the sum of $1 third$ and $1 over 6$ is $3 over 6$ .

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