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Mathematics

Grade6

Easy

Question

An oil tin contains $13 fraction numerator 1 over denominator 2 end fraction$ liters of oil which is poured into $4 fraction numerator 1 over denominator 2 end fraction$ liters bottles. Find the number of bottles required to fill $13 fraction numerator 1 over denominator 2 end fraction$ liters of oil.

1
2
3
4

hint Hint:

To find the number of bottles required we divide the quantity of oil to be poured by capacity of each bottle .
To simplify the division convert both mixed fractions to improper fractions.

The correct answer is: 3

The capacity of each bottle is $4 fraction numerator 1 over denominator 2 end fraction$ liters ; the total quantity oil to be poured is $13 fraction numerator 1 over denominator 2 end fraction$ liters
The numbers of bottles required $equals 13 fraction numerator 1 over denominator 2 end fraction divided by 4 fraction numerator 1 over denominator 2 end fraction$
$equals fraction numerator 27 over denominator 2 end fraction divided by fraction numerator 9 over denominator 2 end fraction equals fraction numerator 27 over denominator 2 end fraction cross times fraction numerator 2 over denominator 9 end fraction equals 3$ bottles.
Therefore, the number of bottles required is 3.

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