Mathematics
Grade6
Easy

Question

An oil tin contains 13 fraction numerator 1 over denominator 2 end fraction liters of oil which is poured into4 fraction numerator 1 over denominator 2 end fraction liters bottles. Find the number of bottles required to fill 13 fraction numerator 1 over denominator 2 end fraction liters of oil.

  1. 1    
  2. 2    
  3. 3    
  4. 4    

Hint:

To find the number of bottles required we divide the quantity of oil to be poured by capacity of each bottle .
To simplify the division convert both mixed fractions to improper fractions.

The correct answer is: 3


    The capacity of each bottle is 4 fraction numerator 1 over denominator 2 end fraction liters  ; the total quantity oil to be poured is  13 fraction numerator 1 over denominator 2 end fraction liters
    The numbers of bottles required equals 13 fraction numerator 1 over denominator 2 end fraction divided by 4 fraction numerator 1 over denominator 2 end fraction
    equals fraction numerator 27 over denominator 2 end fraction divided by fraction numerator 9 over denominator 2 end fraction equals fraction numerator 27 over denominator 2 end fraction cross times fraction numerator 2 over denominator 9 end fraction equals 3 bottles.
    Therefore, the number of bottles required is 3.

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