Mathematics

Grade6

Easy

Question

# Complete the multiplication sentence.

3 × ? = .

Hint:

### In the question, given . It is required to find the number in place of the question mark. To find that number we just need to divide by 3. Since we all know that if a number multiplied by 3 gives then the number is equal to divided by 3.

## The correct answer is:

### Step by step solution:

Given,

Let us consider the number required to be found as 'x'.

Now, the equation becomes

Now, we all know that in fraction division, we can simply reciprocate the number to the right of the '' sign and replace the '' sign with 'x' sign and perform multiplication.

Therefore,

Here, the 3 in the numerator of the first fraction gets reduced by the 3 in the denominator of the second fraction.

Thus, we get x = which is the required answer.

Hence, option (d) is the correct option.

### Related Questions to study

MathematicsVideo

### Choose the correct answer.

Also, consider the multiplication sentence.

2 × ? = .

### Choose the correct answer.

Also, consider the multiplication sentence.

2 × ? = .

MathematicsGrade6

MathematicsVideo

### Two-thirds of the students in your class are boys. One-eighth of the boys play soccer. The fraction of the number of boys in your class who play soccer is~~.~~

Here, it is given that 2/3 pf the students in the class are boys and among the boys 1/8 of the boys play soccer. We have to find the fraction of boys who play soccer in the class.

Number of boys who play soccer = 2⁄3 × 1⁄8

= (2×1)⁄(3×8)

= 2⁄24

= 1⁄12.

Hence, the correct option is C.

Number of boys who play soccer = 2⁄3 × 1⁄8

= (2×1)⁄(3×8)

= 2⁄24

= 1⁄12.

Hence, the correct option is C.

### Two-thirds of the students in your class are boys. One-eighth of the boys play soccer. The fraction of the number of boys in your class who play soccer is~~.~~

MathematicsGrade6

Here, it is given that 2/3 pf the students in the class are boys and among the boys 1/8 of the boys play soccer. We have to find the fraction of boys who play soccer in the class.

Number of boys who play soccer = 2⁄3 × 1⁄8

= (2×1)⁄(3×8)

= 2⁄24

= 1⁄12.

Hence, the correct option is C.

Number of boys who play soccer = 2⁄3 × 1⁄8

= (2×1)⁄(3×8)

= 2⁄24

= 1⁄12.

Hence, the correct option is C.

MathematicsVideo

### Name the operation you would use.

The bleachers at a football game are full, and of the fans in the bleachers are rooting for the home team. Select the fraction of the bleachers filled with home-team fans.

We are given that 7/8 of the bleachers in a football game are full and 1/2 of the fans in the bleachers are supporting the home team. We have to find the operations by which we can find the number of fans in the bleachers supporting the home team.

Number of fans who are supporting the home team = 7⁄8 × ½

= 7⁄16.

So, 7/16 of the fans in the bleachers are supporting the home team and we found it by multiplication.

Hence, the correct option is A.

Number of fans who are supporting the home team = 7⁄8 × ½

= 7⁄16.

So, 7/16 of the fans in the bleachers are supporting the home team and we found it by multiplication.

Hence, the correct option is A.

### Name the operation you would use.

The bleachers at a football game are full, and of the fans in the bleachers are rooting for the home team. Select the fraction of the bleachers filled with home-team fans.

MathematicsGrade6

We are given that 7/8 of the bleachers in a football game are full and 1/2 of the fans in the bleachers are supporting the home team. We have to find the operations by which we can find the number of fans in the bleachers supporting the home team.

Number of fans who are supporting the home team = 7⁄8 × ½

= 7⁄16.

So, 7/16 of the fans in the bleachers are supporting the home team and we found it by multiplication.

Hence, the correct option is A.

Number of fans who are supporting the home team = 7⁄8 × ½

= 7⁄16.

So, 7/16 of the fans in the bleachers are supporting the home team and we found it by multiplication.

Hence, the correct option is A.

MathematicsVideo

### =

### =

MathematicsGrade6

Mathematics

### A team of runners is needed to run a -mile relay race. If each runner must run mile. Find the number of runners they need to run the race.

Here, we have to find the number of runners needed to complete a ¼ mile relay race if each runner must run 1⁄16 mile.

Let the number of runners needed be x.

Then, x × 1⁄16 = ¼

=> x = ¼ ÷ 1⁄16

=> x = ¼ × 16

=> x = 4.

So, the number runners needed is 4 and the correct option is A.

Let the number of runners needed be x.

Then, x × 1⁄16 = ¼

=> x = ¼ ÷ 1⁄16

=> x = ¼ × 16

=> x = 4.

So, the number runners needed is 4 and the correct option is A.

### A team of runners is needed to run a -mile relay race. If each runner must run mile. Find the number of runners they need to run the race.

MathematicsGrade6

Here, we have to find the number of runners needed to complete a ¼ mile relay race if each runner must run 1⁄16 mile.

Let the number of runners needed be x.

Then, x × 1⁄16 = ¼

=> x = ¼ ÷ 1⁄16

=> x = ¼ × 16

=> x = 4.

So, the number runners needed is 4 and the correct option is A.

Let the number of runners needed be x.

Then, x × 1⁄16 = ¼

=> x = ¼ ÷ 1⁄16

=> x = ¼ × 16

=> x = 4.

So, the number runners needed is 4 and the correct option is A.

MathematicsVideo

### Multiply .

Here, we have to multiply 2⁄6 and 3⁄5.

We have, 2⁄6 × 3⁄5

= (2×3)⁄(6×5)

= 6⁄30

= 1⁄5.

Hence, the correct option is A.

We have, 2⁄6 × 3⁄5

= (2×3)⁄(6×5)

= 6⁄30

= 1⁄5.

Hence, the correct option is A.

### Multiply .

MathematicsGrade6

Here, we have to multiply 2⁄6 and 3⁄5.

We have, 2⁄6 × 3⁄5

= (2×3)⁄(6×5)

= 6⁄30

= 1⁄5.

Hence, the correct option is A.

We have, 2⁄6 × 3⁄5

= (2×3)⁄(6×5)

= 6⁄30

= 1⁄5.

Hence, the correct option is A.

MathematicsVideo

### Simplify =

Here, we have to multiply 1⁄3 and 1⁄6.

We have, 1⁄3 × 1⁄6

= (1×1)⁄(3×6)

= 1⁄18.

Hence, the correct option is A.

We have, 1⁄3 × 1⁄6

= (1×1)⁄(3×6)

= 1⁄18.

Hence, the correct option is A.

### Simplify =

MathematicsGrade6

Here, we have to multiply 1⁄3 and 1⁄6.

We have, 1⁄3 × 1⁄6

= (1×1)⁄(3×6)

= 1⁄18.

Hence, the correct option is A.

We have, 1⁄3 × 1⁄6

= (1×1)⁄(3×6)

= 1⁄18.

Hence, the correct option is A.

MathematicsVideo

### Simplify

Here, we have to multiply 5⁄6 and 2⁄3.

We have, 5⁄6 × 2⁄3

= (5×2)⁄(6×3)

= 10⁄18.

Hence, the correct option is A.

We have, 5⁄6 × 2⁄3

= (5×2)⁄(6×3)

= 10⁄18.

Hence, the correct option is A.

### Simplify

MathematicsGrade6

Here, we have to multiply 5⁄6 and 2⁄3.

We have, 5⁄6 × 2⁄3

= (5×2)⁄(6×3)

= 10⁄18.

Hence, the correct option is A.

We have, 5⁄6 × 2⁄3

= (5×2)⁄(6×3)

= 10⁄18.

Hence, the correct option is A.

MathematicsVideo

### Simplify

Here, we have to multiply 3⁄5 and 2⁄9.

We have, 3⁄5 × 2⁄9

= (3×2)⁄(5×9)

= 6⁄45.

Hence, the correct option is B.

We have, 3⁄5 × 2⁄9

= (3×2)⁄(5×9)

= 6⁄45.

Hence, the correct option is B.

### Simplify

MathematicsGrade6

Here, we have to multiply 3⁄5 and 2⁄9.

We have, 3⁄5 × 2⁄9

= (3×2)⁄(5×9)

= 6⁄45.

Hence, the correct option is B.

We have, 3⁄5 × 2⁄9

= (3×2)⁄(5×9)

= 6⁄45.

Hence, the correct option is B.

MathematicsVideo

### Simplify

Here, we have to find the product of 3⁄5 and 3⁄8.

We have, 3⁄5 × 3⁄8

= (3×3)⁄(5×8)

= 9⁄40.

hence, the correct option is A.

We have, 3⁄5 × 3⁄8

= (3×3)⁄(5×8)

= 9⁄40.

hence, the correct option is A.

### Simplify

MathematicsGrade6

Here, we have to find the product of 3⁄5 and 3⁄8.

We have, 3⁄5 × 3⁄8

= (3×3)⁄(5×8)

= 9⁄40.

hence, the correct option is A.

We have, 3⁄5 × 3⁄8

= (3×3)⁄(5×8)

= 9⁄40.

hence, the correct option is A.

MathematicsVideo

### =

Step by step solution:

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.

Hence, we get

Thus, the correct option is option (a)

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.

Hence, we get

Thus, the correct option is option (a)

### =

MathematicsGrade6

Step by step solution:

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.

Hence, we get

Thus, the correct option is option (a)

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.

Hence, we get

Thus, the correct option is option (a)

MathematicsVideo

### =

Step by step solution:

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.

Hence,

Thus, the correct option is option (c)

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.

Hence,

Thus, the correct option is option (c)

### =

MathematicsGrade6

Step by step solution:

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.

Hence,

Thus, the correct option is option (c)

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.

Hence,

Thus, the correct option is option (c)

MathematicsVideo

### George has pan of brownies. He eats of them. The fraction of brownies George ate. is

Step by step solution:

Given,

George had pan of brownies.

The fraction that he ate =

Now, to find the fraction of brownies George had we need to multiply the fraction he ate by the total amount he had.

Therefore, the fraction of brownies George had =

Thus, the correct option is option (d)

Given,

George had pan of brownies.

The fraction that he ate =

Now, to find the fraction of brownies George had we need to multiply the fraction he ate by the total amount he had.

Therefore, the fraction of brownies George had =

Thus, the correct option is option (d)

### George has pan of brownies. He eats of them. The fraction of brownies George ate. is

MathematicsGrade6

Step by step solution:

Given,

George had pan of brownies.

The fraction that he ate =

Now, to find the fraction of brownies George had we need to multiply the fraction he ate by the total amount he had.

Therefore, the fraction of brownies George had =

Thus, the correct option is option (d)

Given,

George had pan of brownies.

The fraction that he ate =

Now, to find the fraction of brownies George had we need to multiply the fraction he ate by the total amount he had.

Therefore, the fraction of brownies George had =

Thus, the correct option is option (d)

MathematicsVideo

### Multiply .

Step by step solution:

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.

Hence,

Thus, the correct option is option (a)

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.

Hence,

Thus, the correct option is option (a)

### Multiply .

MathematicsGrade6

Step by step solution:

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.

Hence,

Thus, the correct option is option (a)

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.

Hence,

Thus, the correct option is option (a)

MathematicsVideo

### Multiply .

Step by step solution:

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.

Hence,

Thus, the correct option is option (a)

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.

Hence,

Thus, the correct option is option (a)

### Multiply .

MathematicsGrade6

Step by step solution:

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.

Hence,

Thus, the correct option is option (a)

The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.

In the given question,

Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.

Hence,

Thus, the correct option is option (a)