Mathematics
Grade6
Easy

Question

Complete the multiplication sentence.

3 × ? = 3 over 7.

  1. 5 over 7
  2. 6 over 7
  3. 4 over 7
  4. 1 over 7

Hint:

In the question, given 3 cross times space ? space equals 3 over 7 . It is required to find the number in place of the question mark. To find that number we just need to divide 3 over 7by 3. Since we all know that if a number multiplied by 3 gives 3 over 7 then the number is equal to 3 over 7 divided by 3.

The correct answer is: 1 over 7


Step by step solution:
Given, 3 cross times space ? space equals 3 over 7
Let us consider the number required to be found as 'x'.
Now, the equation becomes 3 cross times x equals 3 over 7
rightwards double arrow space x space equals space 3 over 7 divided by 3
Now, we all know that in fraction division, we can simply reciprocate the number to the right of the 'divided by' sign and replace the 'divided by' sign with 'x' sign and perform multiplication.
Therefore, x equals 3 over 7 cross times 1 third
rightwards double arrow x equals 1 over 7
Here, the 3 in the numerator of the first fraction gets reduced by the 3 in the denominator of the second fraction.
Thus, we get x = 1 over 7 which is the required answer.
Hence, option (d) is the correct option.

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2 × ? = 3 over 4.

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Two-thirds of the students in your class are boys. One-eighth of the boys play soccer. The fraction of the number of boys in your class who play soccer is.

Here, it is given that 2/3 pf the students in the class are boys and among the boys 1/8 of the boys play soccer. We have to find the fraction of boys who play soccer in the class.
Number of boys who play soccer = 2⁄3 × 1⁄8
= (2×1)⁄(3×8)
= 2⁄24
= 1⁄12.
Hence, the correct option is C.

Two-thirds of the students in your class are boys. One-eighth of the boys play soccer. The fraction of the number of boys in your class who play soccer is.

MathematicsGrade6
Here, it is given that 2/3 pf the students in the class are boys and among the boys 1/8 of the boys play soccer. We have to find the fraction of boys who play soccer in the class.
Number of boys who play soccer = 2⁄3 × 1⁄8
= (2×1)⁄(3×8)
= 2⁄24
= 1⁄12.
Hence, the correct option is C.
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Name the operation you would use.
The bleachers at a football game are 7 over 8 full, and 1 half of the fans in the bleachers are rooting for the home team. Select the fraction of the bleachers filled with home-team fans.

We are given that 7/8 of the bleachers in a football game are full and 1/2 of the fans in the bleachers are supporting the home team. We have to find the operations by which we can find the number of fans in the bleachers supporting the home team.
Number of fans who are supporting the home team = 7⁄8 × ½
= 7⁄16.
So, 7/16 of the fans in the bleachers are supporting the home team and we found it by multiplication.
Hence, the correct option is A.

Name the operation you would use.
The bleachers at a football game are 7 over 8 full, and 1 half of the fans in the bleachers are rooting for the home team. Select the fraction of the bleachers filled with home-team fans.

MathematicsGrade6
We are given that 7/8 of the bleachers in a football game are full and 1/2 of the fans in the bleachers are supporting the home team. We have to find the operations by which we can find the number of fans in the bleachers supporting the home team.
Number of fans who are supporting the home team = 7⁄8 × ½
= 7⁄16.
So, 7/16 of the fans in the bleachers are supporting the home team and we found it by multiplication.
Hence, the correct option is A.
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A team of runners is needed to run a 1 fourth-mile relay race. If each runner must run 1 over 16 mile. Find the number of runners they need to run the race.

Here, we have to find the number of runners needed to complete a ¼ mile relay race if each runner must run 1⁄16 mile.
Let the number of runners needed be x.
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=> x = ¼ × 16
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So, the number runners needed is 4 and the correct option is A.

A team of runners is needed to run a 1 fourth-mile relay race. If each runner must run 1 over 16 mile. Find the number of runners they need to run the race.

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Here, we have to find the number of runners needed to complete a ¼ mile relay race if each runner must run 1⁄16 mile.
Let the number of runners needed be x.
Then, x × 1⁄16 = ¼
=> x = ¼ ÷ 1⁄16
=> x = ¼ × 16
=> x = 4.
So, the number runners needed is 4 and the correct option is A.
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Here, we have to multiply 2⁄6 and 3⁄5.
We have, 2⁄6 × 3⁄5
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Hence, the correct option is A.

Multiply 2 over 6 cross times 3 over 5.

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Here, we have to multiply 2⁄6 and 3⁄5.
We have, 2⁄6 × 3⁄5
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Hence, the correct option is A.
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Here, we have to multiply 1⁄3 and 1⁄6.
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Simplify 1 third cross times 1 over 6=

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Here, we have to multiply 1⁄3 and 1⁄6.
We have, 1⁄3 × 1⁄6
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Simplify 5 over 6 cross times 2 over 3

Here, we have to multiply 5⁄6 and 2⁄3.
We have, 5⁄6 × 2⁄3
= (5×2)⁄(6×3)
= 10⁄18.
Hence, the correct option is A.

Simplify 5 over 6 cross times 2 over 3

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Here, we have to multiply 5⁄6 and 2⁄3.
We have, 5⁄6 × 2⁄3
= (5×2)⁄(6×3)
= 10⁄18.
Hence, the correct option is A.
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Simplify 3 over 5 cross times 2 over 9

Here, we have to multiply 3⁄5 and 2⁄9.
We have, 3⁄5 × 2⁄9
= (3×2)⁄(5×9)
= 6⁄45.
Hence, the correct option is B.

Simplify 3 over 5 cross times 2 over 9

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Here, we have to multiply 3⁄5 and 2⁄9.
We have, 3⁄5 × 2⁄9
= (3×2)⁄(5×9)
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Hence, the correct option is B.
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Here, we have to find the product of 3⁄5 and 3⁄8.
We have, 3⁄5 × 3⁄8
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hence, the correct option is A.

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Here, we have to find the product of 3⁄5 and 3⁄8.
We have, 3⁄5 × 3⁄8
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3 over 8 cross times 2 over 3=

Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 3 over 8 cross times 2 over 3 equals 6 over 24
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.
Hence, we get 6 over 24 equals 1 fourth
Thus, the correct option is option (a)

3 over 8 cross times 2 over 3=

MathematicsGrade6
Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 3 over 8 cross times 2 over 3 equals 6 over 24
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.
Hence, we get 6 over 24 equals 1 fourth
Thus, the correct option is option (a)
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1 half cross times 4 over 5=

Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 1 half cross times 4 over 5 equals fraction numerator 1 cross times 4 over denominator 2 cross times 5 end fraction equals 4 over 10
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.
Hence, 4 over 10 equals 2 over 5
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1 half cross times 4 over 5=

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Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 1 half cross times 4 over 5 equals fraction numerator 1 cross times 4 over denominator 2 cross times 5 end fraction equals 4 over 10
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.
Hence, 4 over 10 equals 2 over 5
Thus, the correct option is option (c)
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George has 1 third pan of brownies. He eats 1 fourth of them. The fraction of brownies George ate. is

Step by step solution:
Given,
George had 1 third pan of brownies.
The fraction that he ate = 1 fourth
Now, to find the fraction of brownies George had we need to multiply the fraction he ate by the total amount he had.
Therefore, the fraction of brownies George had = 1 fourth cross times 1 third equals 1 over 12
Thus, the correct option is option (d)

George has 1 third pan of brownies. He eats 1 fourth of them. The fraction of brownies George ate. is

MathematicsGrade6
Step by step solution:
Given,
George had 1 third pan of brownies.
The fraction that he ate = 1 fourth
Now, to find the fraction of brownies George had we need to multiply the fraction he ate by the total amount he had.
Therefore, the fraction of brownies George had = 1 fourth cross times 1 third equals 1 over 12
Thus, the correct option is option (d)
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Multiply 2 over 6 cross times 3 over 5 .

Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 2 over 6 cross times 3 over 5 equals fraction numerator 2 cross times 3 over denominator 6 cross times 5 end fraction equals 6 over 30
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.
Hence, 6 over 30 equals 1 fifth
Thus, the correct option is option (a)

Multiply 2 over 6 cross times 3 over 5 .

MathematicsGrade6
Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 2 over 6 cross times 3 over 5 equals fraction numerator 2 cross times 3 over denominator 6 cross times 5 end fraction equals 6 over 30
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.
Hence, 6 over 30 equals 1 fifth
Thus, the correct option is option (a)
Grade6
MathematicsVideo

Multiply 1 fifth cross times 2 over 10 .

Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question,  1 fifth cross times 2 over 10 equals 2 over 50
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.
Hence, 2 over 50 equals 1 over 25
Thus, the correct option is option (a)

Multiply 1 fifth cross times 2 over 10 .

MathematicsGrade6
Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question,  1 fifth cross times 2 over 10 equals 2 over 50
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.
Hence, 2 over 50 equals 1 over 25
Thus, the correct option is option (a)
parallel

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