Mathematics
Grade-4-
Easy
Question
Convert the fraction 
into decimal form.
- 0.2
- 0.4
- 0.8
- 1.2
Hint:
In this question we will first convert the fraction into its simplest form then into decimal. To convert any fraction into decimal number we have to divide numerator by denominator. When numerator is less than denominator we have to first write a decimal in quotient which gives a 0 in the right hand side of the dividend after which we can divide the numbers as usual. During division we will write the quotient in the right hand side of the decimal.
The correct answer is: 0.8
Decimal form of = 
= 
= 0.8
Related Questions to study
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Convert the decimal 1.5 into the fraction.
decimal 1.5 into fraction
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Equivalent fraction of = 
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Convert the decimal 0.2 into a fraction.
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Mathematics
If a game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the number 1,2,3……12 , then the probability that it will point to an odd number is:
Total number of outcome = 12
No. possible outcome(no. odd nos. from 1 to 12 ) = 6
Probability =
So, the probability of getting the odd number is
.
No. possible outcome(no. odd nos. from 1 to 12 ) = 6
Probability =
So, the probability of getting the odd number is
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MathematicsGrade-4-
Total number of outcome = 12
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Probability =
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.Mathematics
In a lottery there are 15 prizes and 30 blanks. A lottery is drawn at random. Then, the probability of a getting prize is_____.
total no. of outcome = 15 +30 = 45
no. of possible outcome(no. of prizes) = 15
Probability =
So, the probability of getting prize if the lottery is picked randomly is
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no. of possible outcome(no. of prizes) = 15
Probability =
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MathematicsGrade-4-
total no. of outcome = 15 +30 = 45
no. of possible outcome(no. of prizes) = 15
Probability =
So, the probability of getting prize if the lottery is picked randomly is.
no. of possible outcome(no. of prizes) = 15
Probability =
So, the probability of getting prize if the lottery is picked randomly is
.Mathematics
There are 2 yellow marbles, 4 red marbles, 6 blue marbles, and 3 green marbles in a bag. Miguel will choose a marble at random from the bag. The probability to get yellow marble is _________.
Total no. of outcomes = 2+4+6+3 = 15
no. of possible outcome ( no. of yellow marbles) = 2
Probability =
So, the probability of getting a yellow marble is.
no. of possible outcome ( no. of yellow marbles) = 2
Probability =
So, the probability of getting a yellow marble is
.There are 2 yellow marbles, 4 red marbles, 6 blue marbles, and 3 green marbles in a bag. Miguel will choose a marble at random from the bag. The probability to get yellow marble is _________.
MathematicsGrade-4-
Total no. of outcomes = 2+4+6+3 = 15
no. of possible outcome ( no. of yellow marbles) = 2
Probability =
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no. of possible outcome ( no. of yellow marbles) = 2
Probability =
So, the probability of getting a yellow marble is
.
Mathematics
The chance of throwing 6 with an ordinary dice is_______.
Total no. of outcome = 6
no. of possible outcome = 1
Probability =
So, the chance of throwing 6 with an ordinary dice is.
no. of possible outcome = 1
Probability =
So, the chance of throwing 6 with an ordinary dice is
.The chance of throwing 6 with an ordinary dice is_______.
MathematicsGrade-4-
Total no. of outcome = 6
no. of possible outcome = 1
Probability =
So, the chance of throwing 6 with an ordinary dice is.
no. of possible outcome = 1
Probability =
So, the chance of throwing 6 with an ordinary dice is
.Mathematics
From a bag of 3 red, 3 blue, 4 white balls. A ball is picked at random. The probability to get white ball is_________.
total number of outcomes = 10
number of possible outcomes ( no. of white balls ) = 4
Probability = 4/10
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number of possible outcomes ( no. of white balls ) = 4
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.From a bag of 3 red, 3 blue, 4 white balls. A ball is picked at random. The probability to get white ball is_________.
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In a box, there are 6 red, 7 blue and 8 green balls. One ball is picked up randomly. The probability that the ball drawn is neither red nor blue is_____.
Total no. of outcomes = 6+7+8 = 21
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Possibility =
so, the probability that ball is neither red nor blue is.
no. of possible outcomes(neither red nor blue i.e. green) = 8
Possibility =
so, the probability that ball is neither red nor blue is
.In a box, there are 6 red, 7 blue and 8 green balls. One ball is picked up randomly. The probability that the ball drawn is neither red nor blue is_____.
MathematicsGrade-4-
Total no. of outcomes = 6+7+8 = 21
no. of possible outcomes(neither red nor blue i.e. green) = 8
Possibility =
so, the probability that ball is neither red nor blue is.
no. of possible outcomes(neither red nor blue i.e. green) = 8
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so, the probability that ball is neither red nor blue is
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Mathematics
A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, then the number of blue balls in a bag is:
Let the probability of getting balls be x.
Then the probability of getting blue ball = 2x
As we know the sum of probability of all the possible outcomes is 1.
So, 2x + x = 1
Let total number of probability be P.
The probability of getting red balls =
but as derived probability of getting red ball = x =
So,
total number of outcome i.e. total no. balls is 15
so, no. blue balls = 15 - 5 =10.
Then the probability of getting blue ball = 2x
As we know the sum of probability of all the possible outcomes is 1.
So, 2x + x = 1
Let total number of probability be P.
The probability of getting red balls =
but as derived probability of getting red ball = x =
So,
total number of outcome i.e. total no. balls is 15
so, no. blue balls = 15 - 5 =10.
A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, then the number of blue balls in a bag is:
MathematicsGrade-4-
Let the probability of getting balls be x.
Then the probability of getting blue ball = 2x
As we know the sum of probability of all the possible outcomes is 1.
So, 2x + x = 1
Let total number of probability be P.
The probability of getting red balls =
but as derived probability of getting red ball = x =
So,
total number of outcome i.e. total no. balls is 15
so, no. blue balls = 15 - 5 =10.
Then the probability of getting blue ball = 2x
As we know the sum of probability of all the possible outcomes is 1.
So, 2x + x = 1
Let total number of probability be P.
The probability of getting red balls =
but as derived probability of getting red ball = x =
So,
total number of outcome i.e. total no. balls is 15
so, no. blue balls = 15 - 5 =10.
Mathematics
From a bag of 2 red, 3 blue and 2 black balls. A ball is picked out at random. The probability to get red ball is_______
Total no. of total outcome = 2+3+2=7
No. of possible outcome ( no. of red balls)= 2
Possibility=
So, probability of getting red ball is
.
No. of possible outcome ( no. of red balls)= 2
Possibility=
So, probability of getting red ball is
.From a bag of 2 red, 3 blue and 2 black balls. A ball is picked out at random. The probability to get red ball is_______
MathematicsGrade-4-
Total no. of total outcome = 2+3+2=7
No. of possible outcome ( no. of red balls)= 2
Possibility=
So, probability of getting red ball is.
No. of possible outcome ( no. of red balls)= 2
Possibility=
So, probability of getting red ball is
.Mathematics
If the sum is 10 when two fair dice are tossed then the probability is__________.
Total number outcomes = 36
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
If the sum is 10 when two fair dice are tossed then the probability is__________.
MathematicsGrade-4-
Total number outcomes = 36
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
Mathematics
A coin has ___.
A coin has one head and one tail.
A coin has ___.
MathematicsGrade-4-
A coin has one head and one tail.
Mathematics
The probability of picking an alphabet from consonants is
Here, we have to find the probability of picking an alphabet from consonant of the English alphabet at random.
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
The probability of picking an alphabet from consonants is
MathematicsGrade-4-
Here, we have to find the probability of picking an alphabet from consonant of the English alphabet at random.
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
Mathematics
The probability of the spinners landing on 1 is
Here, we are given a circular spinners with number written on it.
We have to find the probability of the spinner landing on 1.
Total number of outcomes = 8.
Number of favourable outcomes = Number of sections with 1 = 3
Probability that the spinner lands on 1 = 3/8
Hence, the correct option is (d).
We have to find the probability of the spinner landing on 1.
Total number of outcomes = 8.
Number of favourable outcomes = Number of sections with 1 = 3
Probability that the spinner lands on 1 = 3/8
Hence, the correct option is (d).
The probability of the spinners landing on 1 is
MathematicsGrade-4-
Here, we are given a circular spinners with number written on it.
We have to find the probability of the spinner landing on 1.
Total number of outcomes = 8.
Number of favourable outcomes = Number of sections with 1 = 3
Probability that the spinner lands on 1 = 3/8
Hence, the correct option is (d).
We have to find the probability of the spinner landing on 1.
Total number of outcomes = 8.
Number of favourable outcomes = Number of sections with 1 = 3
Probability that the spinner lands on 1 = 3/8
Hence, the correct option is (d).
