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Mathematics

Grade9

Easy

Question

$cos invisible function application 40 to the power of ring operator$ =?

$\sin 50^{\circ}$
$\cos 50^{\circ}$
$\tan 50^{\circ}$
$\sin 40^{\circ}$

hint Hint:

Find the equivalent cos value

The correct answer is: $sin invisible function application 50 to the power of ring operator$

$cos invisible function application 40 to the power of ring operator equals cos invisible function application left parenthesis 90 minus 50 right parenthesis$
$equals sin invisible function application 50 to the power of ring operator$

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