Mathematics
Grade-7
Easy

Question

Determine the distance between 2.5 and - 0.5 on the number line shown

  1. 2
  2. 3
  3. 4
  4. 5

Hint:

As we know to find the solution we have to find the diffrence between them.

The correct answer is: 3


    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    So, we will subract -0.5 from 2.5
    |2.5 – (-0.5) | = |2.5 + 0.5| = 3 units.

    Related Questions to study

    Grade-7
    Mathematics

    The distance between the numbers -4 and 2 on the number line is _____.

    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    open vertical bar negative 4 minus 2 close vertical bar
open vertical bar negative 6 close vertical bar
6

    So, the distance between -4 and 2 is 6 units 

    The distance between the numbers -4 and 2 on the number line is _____.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    open vertical bar negative 4 minus 2 close vertical bar
open vertical bar negative 6 close vertical bar
6

    So, the distance between -4 and 2 is 6 units 

    Grade-7
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    Determine the value of -0.4 ÷ 0.3.

    STEP BY STEP SOLUTON
    negative 0.4 space divided by space 0.3
C o n v e r t i n g space d e c i m a l s space i n t o space f r a c t i o n space
space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 3 over 10 space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 10 over 3 space equals space fraction numerator negative 40 over denominator 30 end fraction space equals space 4 over 3

    Determine the value of -0.4 ÷ 0.3.

    MathematicsGrade-7
    STEP BY STEP SOLUTON
    negative 0.4 space divided by space 0.3
C o n v e r t i n g space d e c i m a l s space i n t o space f r a c t i o n space
space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 3 over 10 space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 10 over 3 space equals space fraction numerator negative 40 over denominator 30 end fraction space equals space 4 over 3
    Grade-7
    Mathematics

    The distance between the two numbers represented (in red) on the number line is ______.

    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    |0.2 – 0.7|
    | 0.5|
    0.5 units.

    So, the distance between 0.2 and 0.7 on a number line is 0.5 units 

    The distance between the two numbers represented (in red) on the number line is ______.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    |0.2 – 0.7|
    | 0.5|
    0.5 units.

    So, the distance between 0.2 and 0.7 on a number line is 0.5 units 

    parallel
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    Mathematics

    Edward bought 3 pencils of equal price of $4.20. The price of each pencil is __________.

    STEP  BY STEP SOLUTION
    Price of 3 pencils = $4.20
    Price of 1 pencil = fraction numerator P r i c e space o f space 3 space p e n c i l s space over denominator 3 space p e n c i l s end fraction
    4.20 space divided by space 3
fraction numerator 420 over denominator space 100 end fraction space divided by space 3 over 1 space equals space 420 over 100 space cross times space 1 third space equals space 420 over 300 space equals space 7 over 5

    Edward bought 3 pencils of equal price of $4.20. The price of each pencil is __________.

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    STEP  BY STEP SOLUTION
    Price of 3 pencils = $4.20
    Price of 1 pencil = fraction numerator P r i c e space o f space 3 space p e n c i l s space over denominator 3 space p e n c i l s end fraction
    4.20 space divided by space 3
fraction numerator 420 over denominator space 100 end fraction space divided by space 3 over 1 space equals space 420 over 100 space cross times space 1 third space equals space 420 over 300 space equals space 7 over 5
    Grade-7
    Mathematics

    The sum or difference of negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses is _____.

    STEP BY STEP SOLUTION
    negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses
W e space w i l l space c o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space
equals negative 3.5 space plus open parentheses negative 56 over 10 close parentheses
N o w space w e space w i l l space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space w e space c a n space a l s o space t a k e space L C M space a n d space t h e n space s o l v e space
equals negative 3.5 minus 5.6
O n space s i m p l i f y i n g space w e space w i l l space g e t space
equals negative 9.1

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    STEP BY STEP SOLUTION
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W e space w i l l space c o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space
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equals negative 3.5 minus 5.6
O n space s i m p l i f y i n g space w e space w i l l space g e t space
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    Determine the value of fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses

    STEP BY STEP SOLUTION
    fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses
O p e n i n g space b r a c k e t s space
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equals space 48 over 18 space equals space fraction numerator negative 24 over denominator 9 end fraction

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    STEP BY STEP SOLUTION
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    The cost of 7 over 2 meters of cloth is $ 231 over 4. The cost of one meter is __________.

    STEP BY STEP SOLUTION
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    231 over 4 space divided by space 7 over 2 space equals space 231 over 2 space cross times space 2 over 7 space equals space 462 over 14 space equals space 33
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    STEP BY STEP SOLUTION
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    STEP BY STEP SOLUTION
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    negative 2 1 fifth plus 1.03
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    STEP BY STEP SOLUTION
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    STEP BY STEP SOLUTION
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    STEP BY STEP SOLUTION
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    STEP BY STEP SOLUTION
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    STEP BY STEP SOLUTION
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equals negative 3.8 plus space 28 over 10
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equals negative 3.8 plus 2.8 equals negative 1.0
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    MathematicsGrade-7
    STEP BY STEP SOLUTION
    negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses
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equals negative 3.8 minus open parentheses negative 28 over 10 close parentheses
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equals negative 3.8 plus space 28 over 10
N o w space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space t a k e space L C M space
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    Determine the value of text  (15)   end text 1 1 fourth space plus space left parenthesis 15 right parenthesis space open parentheses negative 3 over 2 close parentheses .

    STEP BY STEP SOLUTION
    ]text  (15)1  end text 1 fourth plus left parenthesis 15 right parenthesis open parentheses negative 3 over 2 close parentheses
T a k i n g space 15 space c o m m o n space f r o m space b o t h
space equals space 15 open square brackets 1 1 fourth space plus space open parentheses negative 3 over 2 close parentheses close square brackets space
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space a n d space o p e n i n g space b r a c k e t s
equals space 15 open square brackets 5 over 4 space minus space 3 over 2 close square brackets space equals space 15 open square brackets fraction numerator 5 space minus space 6 over denominator 4 end fraction close square brackets space
equals space 15 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses
M i l t i p l y i n g space 15 space i n s i d e space b r a c k e t
space equals space fraction numerator negative 15 over denominator 4 end fraction

    Determine the value of text  (15)   end text 1 1 fourth space plus space left parenthesis 15 right parenthesis space open parentheses negative 3 over 2 close parentheses .

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    ]text  (15)1  end text 1 fourth plus left parenthesis 15 right parenthesis open parentheses negative 3 over 2 close parentheses
T a k i n g space 15 space c o m m o n space f r o m space b o t h
space equals space 15 open square brackets 1 1 fourth space plus space open parentheses negative 3 over 2 close parentheses close square brackets space
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space a n d space o p e n i n g space b r a c k e t s
equals space 15 open square brackets 5 over 4 space minus space 3 over 2 close square brackets space equals space 15 open square brackets fraction numerator 5 space minus space 6 over denominator 4 end fraction close square brackets space
equals space 15 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses
M i l t i p l y i n g space 15 space i n s i d e space b r a c k e t
space equals space fraction numerator negative 15 over denominator 4 end fraction
    parallel
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    The sum or difference of  5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses is _____.

    STEP BY STEP SOLUTION
    5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses
O p e n space t h e space b r a c k e t
equals 5 3 over 4 minus 6 1 fourth
C o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals 23 over 4 space minus space 25 over 4
N o w space t a k i n g space L c m space o r space w e space c a n space c o n v e r t space i t space i n space d e c i m a l s
equals fraction numerator 23 minus 25 over denominator 4 end fraction
equals fraction numerator negative 2 over denominator 4 end fraction space o r space minus 1 half

    The sum or difference of  5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses is _____.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses
O p e n space t h e space b r a c k e t
equals 5 3 over 4 minus 6 1 fourth
C o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals 23 over 4 space minus space 25 over 4
N o w space t a k i n g space L c m space o r space w e space c a n space c o n v e r t space i t space i n space d e c i m a l s
equals fraction numerator 23 minus 25 over denominator 4 end fraction
equals fraction numerator negative 2 over denominator 4 end fraction space o r space minus 1 half
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    Mathematics

    The sum or difference of  5 over 9 plus fraction numerator negative 8 over denominator 9 end fraction  is _________.

    STEP BY STEP SOLUTION
    5 over 9 plus open parentheses fraction numerator negative 8 over denominator 9 end fraction close parentheses
O p e n i n g space b r a c k e t space
equals 5 over 9 minus 8 over 9
T a k i n g space L C M thin space
equals fraction numerator 5 minus 8 over denominator 9 end fraction equals fraction numerator negative 3 over denominator 9 end fraction

    The sum or difference of  5 over 9 plus fraction numerator negative 8 over denominator 9 end fraction  is _________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    5 over 9 plus open parentheses fraction numerator negative 8 over denominator 9 end fraction close parentheses
O p e n i n g space b r a c k e t space
equals 5 over 9 minus 8 over 9
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equals fraction numerator 5 minus 8 over denominator 9 end fraction equals fraction numerator negative 3 over denominator 9 end fraction
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    The sum or difference of fraction numerator negative 4 over denominator 5 end fraction plus 7 over 5  is ___________.

    STEP BY STEP SOLUTION
    fraction numerator negative 4 over denominator 5 end fraction plus 7 over 5
T a k i n g space L C M thin space o r space c o n v e r t i n g space i n t o space d e c i m a l s space
equals fraction numerator negative 4 plus 7 over denominator 5 end fraction equals 3 over 5

    The sum or difference of fraction numerator negative 4 over denominator 5 end fraction plus 7 over 5  is ___________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    fraction numerator negative 4 over denominator 5 end fraction plus 7 over 5
T a k i n g space L C M thin space o r space c o n v e r t i n g space i n t o space d e c i m a l s space
equals fraction numerator negative 4 plus 7 over denominator 5 end fraction equals 3 over 5
    parallel

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