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Mathematics

Grade-7

Easy

Question

Determine the value of $text (15) end text 1 1 fourth space plus space left parenthesis 15 right parenthesis space open parentheses negative 3 over 2 close parentheses$ .

$- \frac{11}{3}$
$- \frac{15}{4}$
$\frac{4}{8}$
$\frac{1}{2}$

hint Hint:

Solving using the BODMASS rule.

The correct answer is: $negative 15 over 4$

STEP BY STEP SOLUTION
] $text (15)1 end text 1 fourth plus left parenthesis 15 right parenthesis open parentheses negative 3 over 2 close parentheses T a k i n g space 15 space c o m m o n space f r o m space b o t h space equals space 15 open square brackets 1 1 fourth space plus space open parentheses negative 3 over 2 close parentheses close square brackets space C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space a n d space o p e n i n g space b r a c k e t s equals space 15 open square brackets 5 over 4 space minus space 3 over 2 close square brackets space equals space 15 open square brackets fraction numerator 5 space minus space 6 over denominator 4 end fraction close square brackets space equals space 15 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses M i l t i p l y i n g space 15 space i n s i d e space b r a c k e t space equals space fraction numerator negative 15 over denominator 4 end fraction$

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