Mathematics
Grade-7
Easy

Question

Determine the value of text  (15)   end text 1 1 fourth space plus space left parenthesis 15 right parenthesis space open parentheses negative 3 over 2 close parentheses .

  1. negative 11 over 3
  2. negative 15 over 4
  3. 4 over 8
  4. 1 half

Hint:

Solving using the BODMASS rule.

The correct answer is: negative 15 over 4


    STEP BY STEP SOLUTION
    ]text  (15)1  end text 1 fourth plus left parenthesis 15 right parenthesis open parentheses negative 3 over 2 close parentheses
T a k i n g space 15 space c o m m o n space f r o m space b o t h
space equals space 15 open square brackets 1 1 fourth space plus space open parentheses negative 3 over 2 close parentheses close square brackets space
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space a n d space o p e n i n g space b r a c k e t s
equals space 15 open square brackets 5 over 4 space minus space 3 over 2 close square brackets space equals space 15 open square brackets fraction numerator 5 space minus space 6 over denominator 4 end fraction close square brackets space
equals space 15 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses
M i l t i p l y i n g space 15 space i n s i d e space b r a c k e t
space equals space fraction numerator negative 15 over denominator 4 end fraction

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