Mathematics
Grade6
Easy

Question

Divide 3 fraction numerator 1 over denominator 5 end fraction by fraction numerator 5 over denominator 8 end fraction.

  1. 5 fraction numerator 3 over denominator 25 end fraction    
  2. 4 fraction numerator 3 over denominator 25 end fraction    
  3. 4 fraction numerator 9 over denominator 25 end fraction    
  4. 4 fraction numerator 15 over denominator 25 end fraction    

hintHint:

To simplify the division we convert the mixed fraction into a improper fraction and when there is a fraction in the denominator then we can multiply the reciprocal of the denominator with the numerator to find the value of the problem.

The correct answer is: 5 fraction numerator 3 over denominator 25 end fraction


    Given ,3 1 fifth divided by 5 over 8
    convert 3 1 fifth into a improper fraction by using
    Improper fraction = fraction numerator open parentheses text Whole number × Denominator end text close parentheses text  + Numerator end text over denominator text Denominator end text end fraction
    3 1 fifth space equals space fraction numerator left parenthesis 3 cross times 5 right parenthesis plus 1 over denominator 5 end fraction space equals 16 over 5
    Now dividing the improper fraction16 over 5 by 5 over 8
    we can multiply the reciprocal of the denominator with the numerator to find the value of the problem.
    16 over 5 space cross times space fraction numerator 8 over denominator 5 space end fraction space equals 128 over 25 space equals space 5 3 over 25
    Therefore ,3 1 fifth divided by 5 over 8 space equals 5 3 over 25.

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