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Mathematics

Grade6

Easy

Question

Divide: $fraction numerator 5 over denominator 9 end fraction divided by 3$

$\frac{1}{27}$
$\frac{5}{27}$
$\frac{5}{9}$
$\frac{4}{9}$

hint Hint:

We can multiply the reciprocal of the denominator with the numerator to find the value of the problem.

The correct answer is: $fraction numerator 5 over denominator 27 end fraction$

Multiply the reciprocal of the denominator with the numerator to find the value of $fraction numerator 5 over denominator 9 end fraction divided by 3$
$fraction numerator 5 over denominator 9 end fraction divided by 3 equals fraction numerator 5 over denominator 9 end fraction cross times fraction numerator 1 over denominator 3 end fraction$ (Reciprocal of 3 is $fraction numerator 1 over denominator 3 end fraction$ )
$equals fraction numerator 5 cross times 1 over denominator 9 cross times 3 end fraction equals fraction numerator 5 over denominator 27 end fraction$
Therefore, $5 over 9 space divided by space 3 space equals space 5 over 27$

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