Mathematics
Grade-7
Easy

Question

Expand the expression. 4(x + 4y - 8z)

  1. 8xyz
  2. 4x + 16y - 32z
  3. 4x + 4y - 8z
  4. 4x + 4y - 8z

hintHint:

General expression evaluation is long enough to solve the given expression.

The correct answer is: 4x + 16y - 32z


    Given Expression:
    4(x + 4y - 8z)
    Since, it is of the form a(b+ c+ d), we can apply Distributive Law which produces ab+ ac + ad as result.
    Similarly, by applying the distributive law to 4(x + 4y - 8z):
    4(x + 4y - 8z)
    =(4 cross times x) + (4 cross times 4 y) + (4 cross times negative 8 z)
    = 4x + 16y -32x.
    Hence, the expression 4(x + 4y - 8z): becomes 4x + 16y -32z after it's expansion.


    In Mathematics , to expand an expression we need to follow some steps. They are :

    * When a grouping is preceded by a + sign, multiply the number outside the grouping without changing the operator in the parentheses.

    Example : a+ (b - c + d) = a + b - c + d.

    * If the grouping is preceded by a - sign, multiply the number outside by all the terms inside the parentheses and change the sign of the terms.

    Example : a - (b - c +d) = a - b + c - d.

    *Apply the distributive property to remove parentheses and combine the like terms.

    Example : a(b + c) = ab + ac.

    Related Questions to study

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    Expand the expression. 5(x - 3)

    Given Expression :
    5(x - 3)
    Since, it is in the form a(b+ c), we can apply Distributive law, that produces ab + ac as a result.
    Similarly, By applying the distributive law to 5(x - 3) becomes,
    5(x - 3)
    = (5 cross times x) - (5 cross times 3)
    = 5x - 15.
    Hence, the expression 5(x - 3) becomes 5x - 15 after it's expansion.

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    Given Expression :
    5(x - 3)
    Since, it is in the form a(b+ c), we can apply Distributive law, that produces ab + ac as a result.
    Similarly, By applying the distributive law to 5(x - 3) becomes,
    5(x - 3)
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    Hence, the expression 5(x - 3) becomes 5x - 15 after it's expansion.

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    Expansion of -8(3a + 5b) yields

    Given Expression:
    -8(3a + 5b)
    Since, it is in the form a(b+ c) we can apply distributive law which produces ab + ac as a result.
    Similarly, by applying the Distributive Law, we get:
    -8(3a + 5b)
    =(negative 8 cross times 3 a)+(negative 8 cross times 5 b)
    = (-24a) + (-40b)
    = -24a - 40b.
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    Expansion of -8(3a + 5b) yields

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    Given Expression:
    -8(3a + 5b)
    Since, it is in the form a(b+ c) we can apply distributive law which produces ab + ac as a result.
    Similarly, by applying the Distributive Law, we get:
    -8(3a + 5b)
    =(negative 8 cross times 3 a)+(negative 8 cross times 5 b)
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    = -24a - 40b.
    Hence, the expression -8(3a + 5b) becomes -24a - 40b after it's expansion.

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    Expand the expression. 2(a + b)

    Given Expression:
    2(a+ b)
    Since, it is in the form a(b+ c) we can apply distributive law which produces ab+ ac as a result.
    Similarly, by applying the Distributive law We get:
    2(a+ b)
    =(2cross timesa) + (2cross timesb)
    = 2a + 2b.
    Hence, the expression 2(a+ b)becomes 2a + 2b after it's expansion. 

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    Given Expression:
    2(a+ b)
    Since, it is in the form a(b+ c) we can apply distributive law which produces ab+ ac as a result.
    Similarly, by applying the Distributive law We get:
    2(a+ b)
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    Hence, the expression 2(a+ b)becomes 2a + 2b after it's expansion. 

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    Expand the expression. 4(7x + 3).

    Given Expression :
    4(7x + 3)
    Since, It is of the form a(b + c), we can apply distributive law which produces ab+ ac.
    Then, By applying the distributive law to a  4(7x + 3), becomes
    =  ( 4cross times7x) + (4cross times3)
    = 28x +12.
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    Expand the expression. 4(7x + 3).

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    Given Expression :
    4(7x + 3)
    Since, It is of the form a(b + c), we can apply distributive law which produces ab+ ac.
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    Expand the expression. 5(x + 2)

    Given Expression :
    5(x+2)
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    Given Expression :
    5(x+2)
    Then, we know distributive law is to be applied in order to remove the parentheses. Hence,
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    Select the expression that contains only like terms.

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    Since, an expression contains the like terms. let, us try to reduce them using expression evaluation.
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    Given That :
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    Since, expression is evaluated with the reduction of like terms and combining their results to get the final expression.
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    parallel
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    Select the expression that contains only like terms.

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    Select the expression that contains only like terms.

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    An expression is having only like terms if and only if it's expression is having only one variable with different coefficients.
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    Find the expression that contains only like terms.

    When an expression is said to have only like terms if it's expression has only one variable with different coefficients.
    Given that:
    we were asked to find the expression having only terms.
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    Find the expression that contains only like terms.

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    When an expression is said to have only like terms if it's expression has only one variable with different coefficients.
    Given that:
    we were asked to find the expression having only terms.
    Hence, let us consider first option 15k + 2k - 4k + 2 , it has k, 2 as variable terms. Hence, It is having unlike terms.
    Similarly, second Option:   16h - 7h + 3g - 9h, it has variables g, h . Hence, it is having unlike terms.
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    Simplify: 5p + 7y + 2t - 3p + 4y

    Since, the given expression is reduced to solve using the like terms present in the expression.
    Given that:
    5p + 7y + 2t - 3p + 4y
    Like terms presents in the expression are 5p, -3p and 7y, 4y.
    Hence, 5p + 7y + 2t - 3p + 4y becomes:
    = (5p-3p) + (7y+4y) + 2t
    = 2p + 11y + 2t
    Therefore, 5p + 7y + 2t - 3p + 4y = 2p + 11y +2t

    Simplify: 5p + 7y + 2t - 3p + 4y

    MathematicsGrade-7

    Since, the given expression is reduced to solve using the like terms present in the expression.
    Given that:
    5p + 7y + 2t - 3p + 4y
    Like terms presents in the expression are 5p, -3p and 7y, 4y.
    Hence, 5p + 7y + 2t - 3p + 4y becomes:
    = (5p-3p) + (7y+4y) + 2t
    = 2p + 11y + 2t
    Therefore, 5p + 7y + 2t - 3p + 4y = 2p + 11y +2t

    parallel

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