Mathematics

Grade10

Easy

Question

Find the option that is a solution to the systems of inequalities.

(0, 0)
(1, 1)
(-4, -2)
(4, -2)

hint Hint:

To be a solution to a system of equations, a point must fall within the common shaded region of all the equations. We check that for all the options and find out the required point.

The correct answer is: (-4, -2)

Step 1 of 1:
Observe that the points (4,-2), (0,0), and (1,1) fall outside the common shaded region of the equations.
But the option (-4, -2) is a solution because it falls in the shaded region.
Final Answer:
The right choice is-- b. (-4, -2)

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Can’t find what you’re looking for?

Find the option that is a solution to the systems of inequalities.

(0, 0)
(1, 1)
(-4, -2)
(4, -2)

To be a solution to a system of equations, a point must fall within the common shaded region of all the equations. We check that for all the options and find out the required point.

The correct answer is: (-4, -2)

Step 1 of 1:
Observe that the points (4,-2), (0,0), and (1,1) fall outside the common shaded region of the equations.
But the option (-4, -2) is a solution because it falls in the shaded region.
Final Answer:
The right choice is-- b. (-4, -2)

Related Questions to study

Rewrite this inequality in "y =" form to graph.
3x - 6y > 12

Rewrite this inequality in "y =" form to graph.
3x - 6y > 12

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Find the option that is NOT a solution to the systems of inequalities.

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Consider the function y < 2x + 3. Find the true statement.

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Find the system of inequalities that matches the graph.

Find the system of inequalities that matches the graph.

Find the option that is not a solution to this system of inequalities.

Find the option that is not a solution to this system of inequalities.

Have a query? Ask a Tutor!!

Can’t find what you’re looking for?

Find the option that is a solution to the systems of inequalities.

(0, 0)(1, 1)(-4, -2)(4, -2)

To be a solution to a system of equations, a point must fall within the common shaded region of all the equations. We check that for all the options and find out the required point.

The correct answer is: (-4, -2)

Step 1 of 1:Observe that the points (4,-2), (0,0), and (1,1) fall outside the common shaded region of the equations.But the option (-4, -2) is a solution because it falls in the shaded region.Final Answer:The right choice is-- b. (-4, -2)

Related Questions to study

Rewrite this inequality in "y =" form to graph. 3x - 6y > 12

Rewrite this inequality in "y =" form to graph. 3x - 6y > 12

Find the option that is NOT a solution to the systems of inequalities.

Find the option that is NOT a solution to the systems of inequalities.

Find the option that is a solution to the systems of inequalities.

Find the option that is a solution to the systems of inequalities.

Find the option that is NOT a solution to the systems of inequalities.

Find the option that is NOT a solution to the systems of inequalities.

Identify the option that is NOT a solution to the systems of inequalities.

Identify the option that is NOT a solution to the systems of inequalities.

You can tell if an inequality will have a solid line by,

You can tell if an inequality will have a solid line by,

Find the option that is NOT a solution to the systems of inequalities.

Find the option that is NOT a solution to the systems of inequalities.

Consider the function y < 2x + 3. Find the true statement.

Consider the function y < 2x + 3. Find the true statement.

Find the system of inequalities that matches the graph.

Find the system of inequalities that matches the graph.

Find the option that is not a solution to this system of inequalities.

Find the option that is not a solution to this system of inequalities.

(0, 0)
(1, 1)
(-4, -2)
(4, -2)

Step 1 of 1:
Observe that the points (4,-2), (0,0), and (1,1) fall outside the common shaded region of the equations.
But the option (-4, -2) is a solution because it falls in the shaded region.
Final Answer:
The right choice is-- b. (-4, -2)

Rewrite this inequality in "y =" form to graph.
3x - 6y > 12

Rewrite this inequality in "y =" form to graph.
3x - 6y > 12