Mathematics
Grade10
Easy

Question

Find the solution of quadratic equation x squared minus 10 equals 54 using square roots.

  1. x equals plus-or-minus 8
  2. x equals plus-or-minus √ 2
  3. x equals plus-or-minus √ 6
  4. x equals plus-or-minus √ left parenthesis 5 divided by 3 right parenthesis

The correct answer is: x equals plus-or-minus 8


    8 x squared minus 10 equals 54
    Adding 10 on both the sides,
    8 x squared minus 10 plus 10 equals 54 plus 10
    8 x squared equals 64
    x squared equals 64 divided by 8
    x squared equals 8
    Taking square root on both the sides of the equation, we get
    √ left parenthesis x squared right parenthesis equals plus-or-minus √ 8
    x equals plus-or-minus 2 √ 2

    Related Questions to study

    Grade10
    Mathematics

    Find the solution of quadratic equation 6 x squared minus 13 equals 23 using square roots.

    6 x squared minus 13 equals 23
    Adding 13 on both the sides,
    6 x squared minus 13 plus 13 equals 23 plus 13
    6 x squared equals 23 plus 13
    6 x squared equals 39
    x squared equals 39 divided by 6
    x squared equals 13 divided by 2
    Taking square root on both the sides of the equation, we get
    √ left parenthesis x squared right parenthesis equals plus-or-minus √ left parenthesis 13 divided by 2 right parenthesis
    x equals plus-or-minus √ left parenthesis 13 divided by 2 right parenthesis

    Find the solution of quadratic equation 6 x squared minus 13 equals 23 using square roots.

    MathematicsGrade10
    6 x squared minus 13 equals 23
    Adding 13 on both the sides,
    6 x squared minus 13 plus 13 equals 23 plus 13
    6 x squared equals 23 plus 13
    6 x squared equals 39
    x squared equals 39 divided by 6
    x squared equals 13 divided by 2
    Taking square root on both the sides of the equation, we get
    √ left parenthesis x squared right parenthesis equals plus-or-minus √ left parenthesis 13 divided by 2 right parenthesis
    x equals plus-or-minus √ left parenthesis 13 divided by 2 right parenthesis
    Grade10
    Mathematics

    Find the solution of quadratic equation x squared plus 1 equals 1 using square roots.

    x squared plus 1 equals 1
    Subtracting ‘1’ from both the sides,
    x squared plus 1 minus 1 equals 1 minus 1
    x squared equals 0
    Taking square root on both the sides of the equation, we get
    √ left parenthesis x squared right parenthesis equals plus-or-minus √ 0
    x equals 0

    Find the solution of quadratic equation x squared plus 1 equals 1 using square roots.

    MathematicsGrade10
    x squared plus 1 equals 1
    Subtracting ‘1’ from both the sides,
    x squared plus 1 minus 1 equals 1 minus 1
    x squared equals 0
    Taking square root on both the sides of the equation, we get
    √ left parenthesis x squared right parenthesis equals plus-or-minus √ 0
    x equals 0
    Grade10
    Mathematics

    Determine the solutions of each of the quadratic equations by inspecting the graph. Give answers correct to 1 decimal place where appropriate.

    The graph cuts the x-axis at x = 3 and x = 4 .so 3 and 4 are root/solution of the equation

    Determine the solutions of each of the quadratic equations by inspecting the graph. Give answers correct to 1 decimal place where appropriate.

    MathematicsGrade10
    The graph cuts the x-axis at x = 3 and x = 4 .so 3 and 4 are root/solution of the equation
    parallel
    Grade10
    Mathematics

    Determine the solutions of each of the quadratic equations by inspecting the graph. Give answers correct to 1 decimal place where appropriate.

    The graph touches the x-axis at so , its both root would be same and that is x=6,6

    Determine the solutions of each of the quadratic equations by inspecting the graph. Give answers correct to 1 decimal place where appropriate.

    MathematicsGrade10
    The graph touches the x-axis at so , its both root would be same and that is x=6,6
    Grade10
    Mathematics

    Convert the quadratic equation straight x squared minus 2.5 straight x plus 1 equals 0  into factored form.

    straight x squared minus 2.5 straight x plus 1 equals 0
2 straight x squared minus 5 straight x plus 2 equals 0
2 straight x squared minus 4 straight x minus straight x plus 2 equals 0
2 straight x left parenthesis straight x minus 2 right parenthesis minus 1 left parenthesis straight x minus 2 right parenthesis equals 0
left parenthesis straight x minus 2 right parenthesis left parenthesis 2 straight x minus 1 right parenthesis equals 0
straight x minus 2 equals 0 comma space 2 straight x minus 1 equals 0
straight x equals 2 comma space straight x equals 1 half

    Convert the quadratic equation straight x squared minus 2.5 straight x plus 1 equals 0  into factored form.

    MathematicsGrade10
    straight x squared minus 2.5 straight x plus 1 equals 0
2 straight x squared minus 5 straight x plus 2 equals 0
2 straight x squared minus 4 straight x minus straight x plus 2 equals 0
2 straight x left parenthesis straight x minus 2 right parenthesis minus 1 left parenthesis straight x minus 2 right parenthesis equals 0
left parenthesis straight x minus 2 right parenthesis left parenthesis 2 straight x minus 1 right parenthesis equals 0
straight x minus 2 equals 0 comma space 2 straight x minus 1 equals 0
straight x equals 2 comma space straight x equals 1 half
    Grade10
    Mathematics

    Write the equation (x-3)(x-4)=0 into the standard form of the quadratic equation and solve.

    Given  the equation   (x-3)(x-4)    =     0
    To write it in Standard form
    Step 1 :
    expanding right side
    (x-3)(x-4)    = x.(x-4)    - 3.( x-4 )  =   x.x  - x.4  - 3.x - 3.-4
    x2-3x-4x+12=0
    Step 2  :
    Adding like terms     we get x2-7x+12=0
    x2-7x+12=0    it , is the standard form .

    Write the equation (x-3)(x-4)=0 into the standard form of the quadratic equation and solve.

    MathematicsGrade10
    Given  the equation   (x-3)(x-4)    =     0
    To write it in Standard form
    Step 1 :
    expanding right side
    (x-3)(x-4)    = x.(x-4)    - 3.( x-4 )  =   x.x  - x.4  - 3.x - 3.-4
    x2-3x-4x+12=0
    Step 2  :
    Adding like terms     we get x2-7x+12=0
    x2-7x+12=0    it , is the standard form .
    parallel
    Grade10
    Mathematics

    Find the option that is NOT a solution to the systems of inequalities.

    Step 1 of 1:
    Observe that the points (3, 1), (4, 3), and (0, 0) fall within the common shaded region of the equations.
    But the option (-2, 0) is not a solution because it does not fall in the shaded region.
    Final Answer:
    The right choice is-- a. (-2, 0)

    Find the option that is NOT a solution to the systems of inequalities.

    MathematicsGrade10
    Step 1 of 1:
    Observe that the points (3, 1), (4, 3), and (0, 0) fall within the common shaded region of the equations.
    But the option (-2, 0) is not a solution because it does not fall in the shaded region.
    Final Answer:
    The right choice is-- a. (-2, 0)
    Grade10
    Mathematics

    Identify the option that is a solution to the systems of inequalities.

    Step 1 of 1:
    Observe that the points (1, -5), (-1, 1), and (-2, 3) fall outside the common shaded region of the equations.
    But the option (2, 3) is a solution because it falls in the shaded region.
    Final Answer:
    The right choice is-- c. (2, 3)

    Identify the option that is a solution to the systems of inequalities.

    MathematicsGrade10
    Step 1 of 1:
    Observe that the points (1, -5), (-1, 1), and (-2, 3) fall outside the common shaded region of the equations.
    But the option (2, 3) is a solution because it falls in the shaded region.
    Final Answer:
    The right choice is-- c. (2, 3)
    Grade10
    Mathematics

    Find the option that is a solution to the systems of inequalities.

    Step 1 of 1:
    Observe that the points (4, 1), (-2, 2), and (3, 0) fall outside the common shaded region of the equations.
    But the option (-1, -3) is a solution because it falls in the shaded region.
    Final Answer:
    The right choice is-- d. (-1, -3)

    Find the option that is a solution to the systems of inequalities.

    MathematicsGrade10
    Step 1 of 1:
    Observe that the points (4, 1), (-2, 2), and (3, 0) fall outside the common shaded region of the equations.
    But the option (-1, -3) is a solution because it falls in the shaded region.
    Final Answer:
    The right choice is-- d. (-1, -3)
    parallel
    Grade10
    Mathematics

    Identify the option that is NOT a solution to the systems of inequalities.

    Step 1 of 1:
    Observe that the points (-3,-1), (-5,0), and (-5,1) fall within the common shaded region of the equations.
    But the option (-2, -1) is not a solution because it does not fall in the shaded region.
    Final Answer:
    The right choice is-- a. (-2, -1)

    Identify the option that is NOT a solution to the systems of inequalities.

    MathematicsGrade10
    Step 1 of 1:
    Observe that the points (-3,-1), (-5,0), and (-5,1) fall within the common shaded region of the equations.
    But the option (-2, -1) is not a solution because it does not fall in the shaded region.
    Final Answer:
    The right choice is-- a. (-2, -1)
    Grade10
    Mathematics

    When you graph an inequality, you use a solid line to use which symbols?

    Step 1 of 1:
    Interpreting the concept explained under the hint section, a solid line is used to denote ≤, ≥.
    Final Answer:
    The right choice is-- c. ≤, ≥

    When you graph an inequality, you use a solid line to use which symbols?

    MathematicsGrade10
    Step 1 of 1:
    Interpreting the concept explained under the hint section, a solid line is used to denote ≤, ≥.
    Final Answer:
    The right choice is-- c. ≤, ≥

    Grade10
    Mathematics

    Find the option that is a solution to the systems of inequalities.

    Step 1 of 1:
    Observe that the points (4,-2), (0,0), and (1,1) fall outside the common shaded region of the equations.
    But the option (-4, -2) is a solution because it falls in the shaded region.
    Final Answer:
    The right choice is-- b. (-4, -2)

    Find the option that is a solution to the systems of inequalities.

    MathematicsGrade10
    Step 1 of 1:
    Observe that the points (4,-2), (0,0), and (1,1) fall outside the common shaded region of the equations.
    But the option (-4, -2) is a solution because it falls in the shaded region.
    Final Answer:
    The right choice is-- b. (-4, -2)
    parallel
    Grade10
    Mathematics

    Rewrite this inequality in "y =" form to graph. 
    3x - 6y > 12

    Step 1 of 1:
    Given inequality 3x - 6y > 12
    or, 6y < 3x - 12
    or, y < fraction numerator 3 x over denominator 6 end fraction minus 12 over 6
    or, y < 1 half x minus 2
    Final Answer:
    The inequality in the "y =" form of the graph is given by-- y < 1 half x minus 2

    Rewrite this inequality in "y =" form to graph. 
    3x - 6y > 12

    MathematicsGrade10
    Step 1 of 1:
    Given inequality 3x - 6y > 12
    or, 6y < 3x - 12
    or, y < fraction numerator 3 x over denominator 6 end fraction minus 12 over 6
    or, y < 1 half x minus 2
    Final Answer:
    The inequality in the "y =" form of the graph is given by-- y < 1 half x minus 2
    Grade10
    Mathematics

    Find the option that is NOT a solution to the systems of inequalities.

    Step 1 of 1:
    Observe that the points (0,0), (3,1), and (2,2) fall within the common shaded region of the equations.
    But the option (-4, 0) is not a solution because it does not fall in the shaded region.
    Final Answer:
    The right choice is-- d. (-4, 0)

    Find the option that is NOT a solution to the systems of inequalities.

    MathematicsGrade10
    Step 1 of 1:
    Observe that the points (0,0), (3,1), and (2,2) fall within the common shaded region of the equations.
    But the option (-4, 0) is not a solution because it does not fall in the shaded region.
    Final Answer:
    The right choice is-- d. (-4, 0)
    Grade10
    Mathematics

    Find the option that is a solution to the systems of inequalities.

    Step 1 of 1:
    Observe that the points (-3,2), (-3,0), and (0,-2) fall outside of the common shaded region of the equations.
    But the option (1, 1) is a solution because it falls within the shaded region.
    Final Answer:
    The right choice is-- b. (1, 1)

    Find the option that is a solution to the systems of inequalities.

    MathematicsGrade10
    Step 1 of 1:
    Observe that the points (-3,2), (-3,0), and (0,-2) fall outside of the common shaded region of the equations.
    But the option (1, 1) is a solution because it falls within the shaded region.
    Final Answer:
    The right choice is-- b. (1, 1)
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.