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Mathematics

Grade10

Easy

Question

Find the solution of quadratic equation $8 x squared minus 10 equals 54$ using square roots

$x = \pm 2 \sqrt 2$
$x = \pm \sqrt 2$
$x = \pm \sqrt 6$
$x = \pm \sqrt (5 / 3)$

The correct answer is: $x equals plus-or-minus 2 √ 2$

$8 x squared minus 10 equals 54$
Adding 10 on both the sides,
$8 x squared minus 10 plus 10 equals 54 plus 10$
$8 x squared equals 64$
$x squared equals 8$
Taking square root on both the sides of the equation, we get
$√ left parenthesis x squared right parenthesis equals plus-or-minus √ 8$
$x equals plus-or-minus 2 √ 2$

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