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Mathematics

Grade10

Easy

Question

Find the solutions of equation $x squared equals 16.$

$x = \pm 2$
$x = \pm 4$
$x = \pm 2 \sqrt 2$
$x = \pm 4 \sqrt 4$

The correct answer is: $x equals plus-or-minus 4$

$x squared equals 16$
Taking square root on both the sides of the equation, we get
$√ left parenthesis x squared right parenthesis equals plus-or-minus √ 16$
$x equals plus-or-minus √ left parenthesis 4 squared right parenthesis$
$x equals plus-or-minus 4$

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