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Mathematics

Grade10

Easy

Question

Find the solutions of the equation $x to the power of 2 end exponent minus 9 x plus 2 equals 0$ using the quadratic formula.

$\frac{9 \pm \sqrt{73}}{2}$
$\frac{9 \pm \sqrt{73}}{1}$
$\frac{9 \pm \sqrt{13}}{2}$
No solution

hint Hint:

In this question, we have to find the solutions of the equation $x to the power of 2 end exponent minus 9 x plus 2 equals 0$ using the quadratic formula. the formula for $x equals fraction numerator negative b plus-or-minus square root of b to the power of 2 end exponent minus 4 a c end root over denominator 2 a end fraction$ . From the equation a= 1, b= (-9) and c= 2. By substituting the given values in the formula, we can find the required solutions.

The correct answer is: $fraction numerator 9 plus-or-minus square root of 73 over denominator 2 end fraction$

$x equals fraction numerator negative b plus-or-minus square root of b to the power of 2 end exponent minus 4 a c end root over denominator 2 a end fraction$
$equals fraction numerator negative open parentheses negative 9 close parentheses plus-or-minus square root of 9 to the power of 2 end exponent minus 4 blank cross times blank 1 blank cross times blank 2 end root over denominator 2 blank cross times blank 1 blank end fraction$
$equals fraction numerator 9 plus-or-minus square root of 81 minus 8 end root over denominator 2 end fraction$
$equals fraction numerator 9 plus-or-minus square root of 73 over denominator 2 end fraction$

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