Mathematics
Grade10
Easy

Question

Find the sum. fraction numerator 3 over denominator x plus 1 end fraction plus fraction numerator 11 over denominator x plus 1 end fraction

  1. fraction numerator text x end text over denominator text (x end text space plus space 1 right parenthesis end fraction
  2. fraction numerator 14 over denominator left parenthesis text x end text space plus space 1 right parenthesis end fraction
  3. fraction numerator 14 text x end text over denominator left parenthesis text x end text space plus space 1 right parenthesis end fraction
  4. fraction numerator left parenthesis text x end text space plus space 1 right parenthesis over denominator 14 end fraction

hintHint:

Equalize the denominators and then add the numerators.

The correct answer is: fraction numerator 14 over denominator left parenthesis text x end text space plus space 1 right parenthesis end fraction


    Given That:
    fraction numerator 3 over denominator x plus 1 end fraction plus fraction numerator 11 over denominator x plus 1 end fraction
    >>>Since, the denominators are same we can add the numerators directly.
    -> fraction numerator 3 over denominator x plus 1 end fraction plus fraction numerator 11 over denominator x plus 1 end fraction = fraction numerator 14 over denominator x plus 1 end fraction
    >>>Therefore, the sum of the given expression is fraction numerator 14 over denominator x plus 1 end fraction.

    fraction numerator 3 over denominator x plus 1 end fraction plus fraction numerator 11 over denominator x plus 1 end fraction equals fraction numerator left parenthesis 3 plus 11 right parenthesis over denominator x plus 1 end fraction equals fraction numerator 14 over denominator x plus 1 end fraction

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