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Mathematics

Grade6

Easy

Question

Find the value of $2 fraction numerator 3 over denominator 5 end fraction divided by 3 fraction numerator 1 over denominator 3 end fraction$ .

$\frac{39}{50}$
$\frac{39}{2}$
$\frac{39}{20}$
$\frac{39}{10}$

hint Hint:

To divide two mixed fractions, we convert them into the improper fractions to simplify .
We can multiply the reciprocal of the denominator with the numerator to find the value of the problem.

The correct answer is: $fraction numerator 39 over denominator 50 end fraction$

convert to improper fraction to simplify
Improper fraction = $fraction numerator open parentheses text Whole number × Denominator end text close parentheses text + Numerator end text over denominator text Denominator end text end fraction$
$2 3 over 5 equals fraction numerator left parenthesis 2 cross times 5 right parenthesis plus 3 over denominator 5 end fraction space equals 13 over 5 space a n d space space space 3 1 third equals fraction numerator left parenthesis 3 cross times 3 right parenthesis plus 1 over denominator 3 end fraction space equals 10 over 3$
Now, $13 over 5 divided by 10 over 3 equals 13 over 5 cross times 3 over 10 left parenthesis space h e r e space fraction numerator 3 over denominator 10 space end fraction space i s space t h e space r e c i p r o c a l space o f space 10 over 3 space right parenthesis equals 39 over 50$
Therefore, $2 3 over 5 divided by 3 1 third space equals 39 over 50$ .

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