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Mathematics

Grade6

Easy

Question

Find the value of $3 fraction numerator 7 over denominator 8 end fraction divided by 7$ .

$\frac{30}{49}$
$\frac{31}{49}$
$\frac{21}{49}$
$\frac{13}{49}$

hint Hint:

Improper fraction = $fraction numerator open parentheses text Whole number × Denominator end text close parentheses text + Numerator end text over denominator text Denominator end text end fraction$
Using this formula find the value of mixed fraction in improper fraction and divide it with 7.

The correct answer is: $fraction numerator 31 over denominator 49 end fraction$

Improper fraction = $fraction numerator open parentheses text Whole number × Denominator end text close parentheses text + Numerator end text over denominator text Denominator end text end fraction$
So, $3 fraction numerator 7 over denominator 8 end fraction equals fraction numerator 8 cross times 3 plus 7 over denominator 8 end fraction equals fraction numerator 31 over denominator 8 end fraction$
We can multiply the reciprocal of the denominator with the numerator to find the value of the problem.
$3 fraction numerator 7 over denominator 8 end fraction divided by 7 equals fraction numerator 31 over denominator 7 end fraction cross times fraction numerator 1 over denominator 7 end fraction open parentheses text reciprocal of 7 is end text fraction numerator 1 over denominator 7 end fraction close parentheses$
$equals fraction numerator 31 over denominator 49 end fraction$
Therefore , $3 fraction numerator 7 over denominator 8 end fraction divided by 7$ $equals fraction numerator 31 over denominator 49 end fraction$ .

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