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Mathematics

Grade-7

Easy

Question

From a rope 11m long, two pieces of lengths $13 over 5$ m and $33 over 10$ m are cut off. Length of the remaining rope is ________.

$\frac{31}{10}$
$\frac{50}{4}$
$\frac{51}{10}$
$\frac{61}{10}$

hint Hint:

To find the length of the remaining rope we will add the length of two pieces that are cut down from the rope and then substract it from the total length.

The correct answer is: $51 over 10$

STEP BY STEP SOLUTION
Total length of rope = 11m
Length of 1st piece = $13 over 5 space m$
Length of 2nd piece = $fraction numerator 33 over denominator 10 space end fraction m$
To find the length of remaining rope we will add the length of 1st and 2nd piece and substract it from
the total length of the rope.
$11 space minus space open parentheses 13 over 5 space plus space 33 over 10 close parentheses T a k i n g space L C M space o f space 5 space & thin space 10 equals space 11 space minus space open parentheses fraction numerator 26 space plus space 33 over denominator 10 end fraction close parentheses space equals space 11 over 1 space minus space 59 over 10 space T a k i n g space L C M space o f space 1 space & 10 equals space fraction numerator 110 space minus space 59 over denominator 10 end fraction space equals space fraction numerator 51 over denominator space 10 end fraction$
The remaining length of the rope is $51 over 10 space m$

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