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Mathematics

Algebra

Easy

Question

$If space space lambda italic space space be space the space ratio space of space the space roots space of space the space quadratic space equation space in space straight x comma 3 m squared x squared plus m left parenthesis m minus 4 right parenthesis x plus 2 equals 0 space space then space space the space least space value space of space space straight m space space for space which space space lambda plus 1 over lambda equals 1 space space is$

$2 - \sqrt{3}$
$4 - 3 \sqrt{2}$
$- 2 + \sqrt{2}$
$4 - 2 \sqrt{3}$

The correct answer is: $4 minus 3 square root of 2$

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