Mathematics
Grade6
Easy

Question

If the lengths of sides of a triangle are, 2 fraction numerator 1 over denominator 5 end fraction c m comma 3 fraction numerator 2 over denominator 5 end fraction c m comma 1 fraction numerator 4 over denominator 5 end fraction c m , then find its perimeter.

  1. 9 fraction numerator 2 over denominator 5 end fraction cm    
  2. 10 fraction numerator 2 over denominator 5 end fraction cm    
  3. 10 fraction numerator 3 over denominator 5 end fraction cm    
  4. 10 fraction numerator 4 over denominator 5 end fraction cm    

Hint:

Perimeter is sum of length of all sides

The correct answer is: 10 fraction numerator 2 over denominator 5 end fraction cm


    Perimeter of a triangle = sum of lengths of all sides.
    equals 2 fraction numerator 1 over denominator 5 end fraction plus 3 fraction numerator 2 over denominator 5 end fraction plus 4 fraction numerator 4 over denominator 5 end fraction
    equals fraction numerator 11 over denominator 5 end fraction plus fraction numerator 17 over denominator 5 end fraction plus fraction numerator 24 over denominator 5 end fraction equals fraction numerator 52 over denominator 5 end fraction text or end text 10 fraction numerator 2 over denominator 5 end fraction

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