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Mathematics

Grade6

Easy

Question

If the lengths of sides of a triangle are, $2 fraction numerator 1 over denominator 5 end fraction c m comma 3 fraction numerator 2 over denominator 5 end fraction c m comma 1 fraction numerator 4 over denominator 5 end fraction c m$ , then find its perimeter.

$9 \frac{2}{5}$ cm
$10 \frac{2}{5}$ cm
$10 \frac{3}{5}$ cm
$10 \frac{4}{5}$ cm

hint Hint:

Perimeter is sum of length of all sides

The correct answer is: $10 fraction numerator 2 over denominator 5 end fraction$ cm

Perimeter of a triangle = sum of lengths of all sides.
$equals 2 fraction numerator 1 over denominator 5 end fraction plus 3 fraction numerator 2 over denominator 5 end fraction plus 4 fraction numerator 4 over denominator 5 end fraction$
$equals fraction numerator 11 over denominator 5 end fraction plus fraction numerator 17 over denominator 5 end fraction plus fraction numerator 24 over denominator 5 end fraction equals fraction numerator 52 over denominator 5 end fraction text or end text 10 fraction numerator 2 over denominator 5 end fraction$

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