Mathematics
Grade-4-
Easy
Question
In a box, there are 6 red, 7 blue and 8 green balls. One ball is picked up randomly. The probability that the ball drawn is neither red nor blue is_____.
Hint:
We have to find the probability that the ball is neither red nor blue. First we will find the number of total number of outcomes. Then we will find the number of possible outcomes i.e. neither red nor blue. Further we will find the probability by dividing number of possible outcomes by total number outcome.
The correct answer is: 
Total no. of outcomes = 6+7+8 = 21
no. of possible outcomes(neither red nor blue i.e. green) = 8
Possibility =
so, the probability that ball is neither red nor blue is
.
Related Questions to study
Mathematics
A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, then the number of blue balls in a bag is:
Let the probability of getting balls be x.
Then the probability of getting blue ball = 2x
As we know the sum of probability of all the possible outcomes is 1.
So, 2x + x = 1

Let total number of probability be P.
The probability of getting red balls =
but as derived probability of getting red ball = x =
So,
total number of outcome i.e. total no. balls is 15
so, no. blue balls = 15 - 5 =10.
Then the probability of getting blue ball = 2x
As we know the sum of probability of all the possible outcomes is 1.
So, 2x + x = 1
Let total number of probability be P.
The probability of getting red balls =
but as derived probability of getting red ball = x =
So,
total number of outcome i.e. total no. balls is 15
so, no. blue balls = 15 - 5 =10.
A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, then the number of blue balls in a bag is:
MathematicsGrade-4-
Let the probability of getting balls be x.
Then the probability of getting blue ball = 2x
As we know the sum of probability of all the possible outcomes is 1.
So, 2x + x = 1

Let total number of probability be P.
The probability of getting red balls =
but as derived probability of getting red ball = x =
So,
total number of outcome i.e. total no. balls is 15
so, no. blue balls = 15 - 5 =10.
Then the probability of getting blue ball = 2x
As we know the sum of probability of all the possible outcomes is 1.
So, 2x + x = 1
Let total number of probability be P.
The probability of getting red balls =
but as derived probability of getting red ball = x =
So,
total number of outcome i.e. total no. balls is 15
so, no. blue balls = 15 - 5 =10.
Mathematics
From a bag of 2 red, 3 blue and 2 black balls. A ball is picked out at random. The probability to get red ball is_______
Total no. of total outcome = 2+3+2=7
No. of possible outcome ( no. of red balls)= 2
Possibility=
So, probability of getting red ball is
.
No. of possible outcome ( no. of red balls)= 2
Possibility=
So, probability of getting red ball is
From a bag of 2 red, 3 blue and 2 black balls. A ball is picked out at random. The probability to get red ball is_______
MathematicsGrade-4-
Total no. of total outcome = 2+3+2=7
No. of possible outcome ( no. of red balls)= 2
Possibility=
So, probability of getting red ball is
.
No. of possible outcome ( no. of red balls)= 2
Possibility=
So, probability of getting red ball is
Mathematics
If the sum is 10 when two fair dice are tossed then the probability is__________.
Total number outcomes = 36
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
If the sum is 10 when two fair dice are tossed then the probability is__________.
MathematicsGrade-4-
Total number outcomes = 36
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
Mathematics
A coin has ___.
A coin has one head and one tail.
A coin has ___.
MathematicsGrade-4-
A coin has one head and one tail.
Mathematics
The probability of picking an alphabet from consonants is
Here, we have to find the probability of picking an alphabet from consonant of the English alphabet at random.
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
The probability of picking an alphabet from consonants is
MathematicsGrade-4-
Here, we have to find the probability of picking an alphabet from consonant of the English alphabet at random.
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
Mathematics
The probability of the spinners landing on 1 is

Here, we are given a circular spinners with number written on it.
We have to find the probability of the spinner landing on 1.
Total number of outcomes = 8.
Number of favourable outcomes = Number of sections with 1 = 3
Probability that the spinner lands on 1 = 3/8
Hence, the correct option is (d).
We have to find the probability of the spinner landing on 1.
Total number of outcomes = 8.
Number of favourable outcomes = Number of sections with 1 = 3
Probability that the spinner lands on 1 = 3/8
Hence, the correct option is (d).
The probability of the spinners landing on 1 is

MathematicsGrade-4-
Here, we are given a circular spinners with number written on it.
We have to find the probability of the spinner landing on 1.
Total number of outcomes = 8.
Number of favourable outcomes = Number of sections with 1 = 3
Probability that the spinner lands on 1 = 3/8
Hence, the correct option is (d).
We have to find the probability of the spinner landing on 1.
Total number of outcomes = 8.
Number of favourable outcomes = Number of sections with 1 = 3
Probability that the spinner lands on 1 = 3/8
Hence, the correct option is (d).
Mathematics
In a lottery there are 10 prizes and 25 blanks. The probability of getting prize in a single draw is
Here, it is given that in a lottery, there are 10 prizes and 25 blanks. We have to find the probability of winning a prize.
Total number of outcomes = Number of prizes + Number of blanks
= 10 + 25
= 35
Number of favourable outcomes = Number of prizes = 10
Therefore, P ( getting a proze ) = 10/35
= 2/7
Hence, the correct option is (a).
Total number of outcomes = Number of prizes + Number of blanks
= 10 + 25
= 35
Number of favourable outcomes = Number of prizes = 10
Therefore, P ( getting a proze ) = 10/35
= 2/7
Hence, the correct option is (a).
In a lottery there are 10 prizes and 25 blanks. The probability of getting prize in a single draw is
MathematicsGrade-4-
Here, it is given that in a lottery, there are 10 prizes and 25 blanks. We have to find the probability of winning a prize.
Total number of outcomes = Number of prizes + Number of blanks
= 10 + 25
= 35
Number of favourable outcomes = Number of prizes = 10
Therefore, P ( getting a proze ) = 10/35
= 2/7
Hence, the correct option is (a).
Total number of outcomes = Number of prizes + Number of blanks
= 10 + 25
= 35
Number of favourable outcomes = Number of prizes = 10
Therefore, P ( getting a proze ) = 10/35
= 2/7
Hence, the correct option is (a).
Mathematics
From a bag of 3 red and 5 blue balls, a ball is drawn randomly. The probability of getting blue is
Here, there are 3 red balls and 5 blue balls in a bag. We have to find the probability of getting a blue balls.
Total number of outcomes = Number of red balls + Number of blue balls
= 3 + 5
= 8
Number of favourable outcomes = Number of blue balls = 5
Therefore, P ( getting a blue ball) = 5/8
Hence, the correct option is (c).
Total number of outcomes = Number of red balls + Number of blue balls
= 3 + 5
= 8
Number of favourable outcomes = Number of blue balls = 5
Therefore, P ( getting a blue ball) = 5/8
Hence, the correct option is (c).
From a bag of 3 red and 5 blue balls, a ball is drawn randomly. The probability of getting blue is
MathematicsGrade-4-
Here, there are 3 red balls and 5 blue balls in a bag. We have to find the probability of getting a blue balls.
Total number of outcomes = Number of red balls + Number of blue balls
= 3 + 5
= 8
Number of favourable outcomes = Number of blue balls = 5
Therefore, P ( getting a blue ball) = 5/8
Hence, the correct option is (c).
Total number of outcomes = Number of red balls + Number of blue balls
= 3 + 5
= 8
Number of favourable outcomes = Number of blue balls = 5
Therefore, P ( getting a blue ball) = 5/8
Hence, the correct option is (c).
Mathematics
If the winning probability is 0.3, then the probability of losing a game is______.
Here, it is given that the probability of winning a game is 0.3.
We have to find the probability of losing the game.
We know, P(E) + P(not E) = 1
So, P(winning a game) +P(losing a game) = 1
Or, P(losing a game) = 1 - P(winning a game)
Or, P(losing a game) = 1 - 0.3
= 0.7
Hence, the correct option is (c).
We have to find the probability of losing the game.
We know, P(E) + P(not E) = 1
So, P(winning a game) +P(losing a game) = 1
Or, P(losing a game) = 1 - P(winning a game)
Or, P(losing a game) = 1 - 0.3
= 0.7
Hence, the correct option is (c).
If the winning probability is 0.3, then the probability of losing a game is______.
MathematicsGrade-4-
Here, it is given that the probability of winning a game is 0.3.
We have to find the probability of losing the game.
We know, P(E) + P(not E) = 1
So, P(winning a game) +P(losing a game) = 1
Or, P(losing a game) = 1 - P(winning a game)
Or, P(losing a game) = 1 - 0.3
= 0.7
Hence, the correct option is (c).
We have to find the probability of losing the game.
We know, P(E) + P(not E) = 1
So, P(winning a game) +P(losing a game) = 1
Or, P(losing a game) = 1 - P(winning a game)
Or, P(losing a game) = 1 - 0.3
= 0.7
Hence, the correct option is (c).
Mathematics
If a coin is tossed thrice, then the probability of getting head twice is_________________.
Here, a coin is tossed thrice are : (H, H, H) , ( H, H,T) , ( H, T, H) , ( T, H, H) , ( T, T, T) , ( T, T, H) , ( T, H, T) , ( H, T, T) .
Total number of outcomes = 8
Number of favourable outcome = Number of outcomes with 2 tails = 3
Therefore, P ( getting head twice) = 3/8
Hence, the correct option is (b).
Total number of outcomes = 8
Number of favourable outcome = Number of outcomes with 2 tails = 3
Therefore, P ( getting head twice) = 3/8
Hence, the correct option is (b).
If a coin is tossed thrice, then the probability of getting head twice is_________________.
MathematicsGrade-4-
Here, a coin is tossed thrice are : (H, H, H) , ( H, H,T) , ( H, T, H) , ( T, H, H) , ( T, T, T) , ( T, T, H) , ( T, H, T) , ( H, T, T) .
Total number of outcomes = 8
Number of favourable outcome = Number of outcomes with 2 tails = 3
Therefore, P ( getting head twice) = 3/8
Hence, the correct option is (b).
Total number of outcomes = 8
Number of favourable outcome = Number of outcomes with 2 tails = 3
Therefore, P ( getting head twice) = 3/8
Hence, the correct option is (b).
Mathematics
Among the following that cannot be a probability is
TO FIND-
Which of the given options can not be used to denote probability.
SOLUTION-
a. 10%
10% = 10/100 = 0.1
b. 10
c. 10 to the power of negative 10 end exponent
10-10 = 1/1010 = 0.0000000001
d. 1 over 10
1/10 = 0.1
Since we know that probability is always a number between 0 and 1, the only option that does not satisfy this condition is option b i.e. 10 because it is greater than 1.
FINAL ANSWER-
Option 'b' i.e. '10' is the correct answer to the given question.
Which of the given options can not be used to denote probability.
SOLUTION-
a. 10%
10% = 10/100 = 0.1
b. 10
c. 10 to the power of negative 10 end exponent
10-10 = 1/1010 = 0.0000000001
d. 1 over 10
1/10 = 0.1
Since we know that probability is always a number between 0 and 1, the only option that does not satisfy this condition is option b i.e. 10 because it is greater than 1.
FINAL ANSWER-
Option 'b' i.e. '10' is the correct answer to the given question.
Among the following that cannot be a probability is
MathematicsGrade-4-
TO FIND-
Which of the given options can not be used to denote probability.
SOLUTION-
a. 10%
10% = 10/100 = 0.1
b. 10
c. 10 to the power of negative 10 end exponent
10-10 = 1/1010 = 0.0000000001
d. 1 over 10
1/10 = 0.1
Since we know that probability is always a number between 0 and 1, the only option that does not satisfy this condition is option b i.e. 10 because it is greater than 1.
FINAL ANSWER-
Option 'b' i.e. '10' is the correct answer to the given question.
Which of the given options can not be used to denote probability.
SOLUTION-
a. 10%
10% = 10/100 = 0.1
b. 10
c. 10 to the power of negative 10 end exponent
10-10 = 1/1010 = 0.0000000001
d. 1 over 10
1/10 = 0.1
Since we know that probability is always a number between 0 and 1, the only option that does not satisfy this condition is option b i.e. 10 because it is greater than 1.
FINAL ANSWER-
Option 'b' i.e. '10' is the correct answer to the given question.
Mathematics
Certain means there’s a ________ chance than an event will happen.
Here, we need to find the probability of a certain event.
A certain event is an event which is sure to happen. The probability of an event is 1 if the number of favourable outcome is equal to the number of total outcomes.
This means that there js 100 percent chance that the event will take place.
Hence, the correct option is (b).
A certain event is an event which is sure to happen. The probability of an event is 1 if the number of favourable outcome is equal to the number of total outcomes.
This means that there js 100 percent chance that the event will take place.
Hence, the correct option is (b).
Certain means there’s a ________ chance than an event will happen.
MathematicsGrade-4-
Here, we need to find the probability of a certain event.
A certain event is an event which is sure to happen. The probability of an event is 1 if the number of favourable outcome is equal to the number of total outcomes.
This means that there js 100 percent chance that the event will take place.
Hence, the correct option is (b).
A certain event is an event which is sure to happen. The probability of an event is 1 if the number of favourable outcome is equal to the number of total outcomes.
This means that there js 100 percent chance that the event will take place.
Hence, the correct option is (b).
Mathematics
If we toss a coin, then the probability of getting tails is_____.
Here, we have to find the probability of getting tails when a coin is tossed.
Possible outcomes are Head (H) and tail (T) i.e (H, T)
Total number of outcomes = 2
Number of favourable outcome = Number of tail = 1
Therefore, P(getting tail) = 1/2
Hence, the correct option is (b).
Possible outcomes are Head (H) and tail (T) i.e (H, T)
Total number of outcomes = 2
Number of favourable outcome = Number of tail = 1
Therefore, P(getting tail) = 1/2
Hence, the correct option is (b).
If we toss a coin, then the probability of getting tails is_____.
MathematicsGrade-4-
Here, we have to find the probability of getting tails when a coin is tossed.
Possible outcomes are Head (H) and tail (T) i.e (H, T)
Total number of outcomes = 2
Number of favourable outcome = Number of tail = 1
Therefore, P(getting tail) = 1/2
Hence, the correct option is (b).
Possible outcomes are Head (H) and tail (T) i.e (H, T)
Total number of outcomes = 2
Number of favourable outcome = Number of tail = 1
Therefore, P(getting tail) = 1/2
Hence, the correct option is (b).
Mathematics
The number of cards in a deck are____.
Here, we have to select the correct option.
A deck of cards has a total of 52 cards.
Hence, the correct option is (a).
A deck of cards has a total of 52 cards.
Hence, the correct option is (a).
The number of cards in a deck are____.
MathematicsGrade-4-
Here, we have to select the correct option.
A deck of cards has a total of 52 cards.
Hence, the correct option is (a).
A deck of cards has a total of 52 cards.
Hence, the correct option is (a).
Mathematics
If we toss a coin, then the probability of getting head is_____
Here, we have to find the probability of getting a head on tossing a coin.
When a coin is tossed, outcomes are Head and Tail.
Total number of outcomes = 1
Number of favourable outcome = Number of Head = 1
Therefore, P ( Head) = 1/2
Hence, the correct option is (a)
When a coin is tossed, outcomes are Head and Tail.
Total number of outcomes = 1
Number of favourable outcome = Number of Head = 1
Therefore, P ( Head) = 1/2
Hence, the correct option is (a)
If we toss a coin, then the probability of getting head is_____
MathematicsGrade-4-
Here, we have to find the probability of getting a head on tossing a coin.
When a coin is tossed, outcomes are Head and Tail.
Total number of outcomes = 1
Number of favourable outcome = Number of Head = 1
Therefore, P ( Head) = 1/2
Hence, the correct option is (a)
When a coin is tossed, outcomes are Head and Tail.
Total number of outcomes = 1
Number of favourable outcome = Number of Head = 1
Therefore, P ( Head) = 1/2
Hence, the correct option is (a)