In the given triangular pyramid, ABCP, YZ is the midsegment of $increment$ APC, XZ is the midsegment of $increment$ ABC, XY is the midsegment of $increment$ ABP. Which of the following statement is true?

Area of $∆$ BPC = $\frac{1}{4}$ Area of $∆$ XYZ
Area of ∆ XYZ = 2 Area of ∆ BPC
Area of ∆ABC = Area of ∆ABP
All the above

hint Hint:

Area of triangle is $1 half cross times b a s e cross times h e i g h t$

The correct answer is: Area of $increment$ BPC = $1 fourth$ Area of $increment$ XYZ

Area of ∆BPC = $1 half space cross times space 1 half$ height of ∆XYZ $cross times space 1 half$ base of ∆XYZ
= $1 fourth$ Area of ∆XYZ

The midpoint theorem refers to the midpoint of the line segment. It defines the coordinate points of the midpoint of the line segment and can be found by taking the average of the coordinates of the given endpoints.

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In the given triangular pyramid, ABCP, YZ is the midsegment of $increment$ APC, XZ is the midsegment of $increment$ ABC, XY is the midsegment of $increment$ ABP. Which of the following statement is true?

Area of $∆$ BPC = $\frac{1}{4}$ Area of $∆$ XYZ
Area of ∆ XYZ = 2 Area of ∆ BPC
Area of ∆ABC = Area of ∆ABP
All the above

Area of triangle is $1 half cross times b a s e cross times h e i g h t$

The correct answer is: Area of $increment$ BPC = $1 fourth$ Area of $increment$ XYZ

Area of ∆BPC = $1 half space cross times space 1 half$ height of ∆XYZ $cross times space 1 half$ base of ∆XYZ
= $1 fourth$ Area of ∆XYZ

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In the given triangular pyramid, ABCP, YZ is the midsegment of APC, XZ is the midsegment of ABC, XY is the midsegment of ABP. Which of the following statement is true?

Area of BPC = Area of XYZArea of ∆ XYZ = 2 Area of ∆ BPCArea of ∆ABC = Area of ∆ABPAll the above

Area of triangle is

The correct answer is: Area of BPC = Area of XYZ

Area of ∆BPC = height of ∆XYZ base of ∆XYZ= Area of ∆XYZ

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In the given triangular pyramid, ABCP, YZ is the midsegment of $increment$ APC, XZ is the midsegment of $increment$ ABC, XY is the midsegment of $increment$ ABP. Which of the following statement is true?

Area of $∆$ BPC = $\frac{1}{4}$ Area of $∆$ XYZ
Area of ∆ XYZ = 2 Area of ∆ BPC
Area of ∆ABC = Area of ∆ABP
All the above

Area of triangle is $1 half cross times b a s e cross times h e i g h t$

The correct answer is: Area of $increment$ BPC = $1 fourth$ Area of $increment$ XYZ

Area of ∆BPC = $1 half space cross times space 1 half$ height of ∆XYZ $cross times space 1 half$ base of ∆XYZ
= $1 fourth$ Area of ∆XYZ