Mathematics
Grade-7
Easy

Question

_______ is the interest on £182 at 11% every year over a period of 12 years.

  1. 200
  2. 145.8  
  3. 154.2
  4. 240.24

hintHint:

Obtain the Simple Interest on the principal value by substituting the values of the given data in simple interest formula.

The correct answer is: 240.24


    I = ? , P = £182 , T = 12 years, R = 0.11
    I = PTR
    I = 182 × 12 × 0.11= £240.24

    >>> Simple Interest = fraction numerator 182 cross times 11 cross times 12 over denominator 100 end fraction
    >>> Simple Interest = 240.24 rupees.

    Related Questions to study

    Grade-7
    Mathematics

    _________ is the principal, if $125 is collected for 5 years by lending at 7% per annum.

    >>> Principal Amount =fraction numerator 125 cross times 100 over denominator 5 cross times 7 end fraction
    >>> Principal Amount = 357.14 rupees.

    _________ is the principal, if $125 is collected for 5 years by lending at 7% per annum.

    MathematicsGrade-7

    >>> Principal Amount =fraction numerator 125 cross times 100 over denominator 5 cross times 7 end fraction
    >>> Principal Amount = 357.14 rupees.

    Grade-7
    Mathematics

    A private lender gives loan at 18% per year in simple interest. The borrower hands over $540 over a period of 3 years in interest. __________ is the amount given on loan.

    >>> Principal Amount = fraction numerator S i m p l e space I n t e r e s t cross times 100 over denominator T i m e cross times r a t e end fraction
    >>> Principal Amount = fraction numerator 540 cross times 100 over denominator 18 cross times 3 end fraction
    >>> principal amount = 1000.

    A private lender gives loan at 18% per year in simple interest. The borrower hands over $540 over a period of 3 years in interest. __________ is the amount given on loan.

    MathematicsGrade-7

    >>> Principal Amount = fraction numerator S i m p l e space I n t e r e s t cross times 100 over denominator T i m e cross times r a t e end fraction
    >>> Principal Amount = fraction numerator 540 cross times 100 over denominator 18 cross times 3 end fraction
    >>> principal amount = 1000.

    Grade-7
    Mathematics

    __________ would be the rate of interest, if £105 is paid per year on a principal amount of £840.

    __________ would be the rate of interest, if £105 is paid per year on a principal amount of £840.

    MathematicsGrade-7
    parallel
    Grade-7
    Mathematics

    If £600 is paid as interest towards a loan of £1500 over a period of 8 years, the rate of interest is _________.

    If £600 is paid as interest towards a loan of £1500 over a period of 8 years, the rate of interest is _________.

    MathematicsGrade-7
    Grade-7
    Mathematics

    If Julie pays £18 per month till 2 years on borrowing £1400, _____ is the rate of interest.

    If Julie pays £18 per month till 2 years on borrowing £1400, _____ is the rate of interest.

    MathematicsGrade-7
    Grade-7
    Mathematics

    _______ is the interest on £356 principal at 8% per year for 5 years.

    _______ is the interest on £356 principal at 8% per year for 5 years.

    MathematicsGrade-7
    parallel
    Grade-7
    Mathematics

    Fred borrows £420 from a person at 2.8% per annum and promises to pay it back in 3 years. Determine the total amount to be paid back by him.

    >>>Simple Interest = fraction numerator 420 cross times 3 cross times 2.8 over denominator 100 end fraction
    >>> Simple Interest = 35.28.
    >>>Therefore, the total amount that he should return = Simple Interest + Principal Amount.
    = 420 + 35.28
    = 455.28

    Fred borrows £420 from a person at 2.8% per annum and promises to pay it back in 3 years. Determine the total amount to be paid back by him.

    MathematicsGrade-7

    >>>Simple Interest = fraction numerator 420 cross times 3 cross times 2.8 over denominator 100 end fraction
    >>> Simple Interest = 35.28.
    >>>Therefore, the total amount that he should return = Simple Interest + Principal Amount.
    = 420 + 35.28
    = 455.28

    Grade-7
    Mathematics

    ______ is the simple interest earned by lending £1600 principal at 7% per annum over a period of 12 years.

    >>> S i m p l e space i n t e r e s t space equals fraction numerator P r i n c i p a l space a m o u n t space cross times T i m e cross times r a t e over denominator 100 end fraction
    >>>Simple Interest = fraction numerator 1600 cross times 7 cross times 12 over denominator 100 end fraction
    >>> Simple Interest = 1344.

    ______ is the simple interest earned by lending £1600 principal at 7% per annum over a period of 12 years.

    MathematicsGrade-7

    >>> S i m p l e space i n t e r e s t space equals fraction numerator P r i n c i p a l space a m o u n t space cross times T i m e cross times r a t e over denominator 100 end fraction
    >>>Simple Interest = fraction numerator 1600 cross times 7 cross times 12 over denominator 100 end fraction
    >>> Simple Interest = 1344.

    Grade-7
    Mathematics

    _______ is the interest on £567 at 4% every year over a period of 6 years.

    >>>S i m p l e r space i n t e r e s t space equals space fraction numerator P r i n c i p a l space a m o u n t cross times T i m e cross times R t a e space o f space i n t e r e s t over denominator 100 end fraction
    >>>Simple interest = fraction numerator 567 cross times 4 cross times 6 over denominator 100 end fraction
    >>>Simple Interest = 130.80

    _______ is the interest on £567 at 4% every year over a period of 6 years.

    MathematicsGrade-7

    >>>S i m p l e r space i n t e r e s t space equals space fraction numerator P r i n c i p a l space a m o u n t cross times T i m e cross times R t a e space o f space i n t e r e s t over denominator 100 end fraction
    >>>Simple interest = fraction numerator 567 cross times 4 cross times 6 over denominator 100 end fraction
    >>>Simple Interest = 130.80

    parallel
    Grade-7
    Mathematics

    Bob wants to find the principal, if £100 is collected for 1 year by lending at 2% per annum.

    Bob wants to find the principal, if £100 is collected for 1 year by lending at 2% per annum.

    MathematicsGrade-7
    Grade-7
    Mathematics

    A bank lends loan at 8% per year in simple interest. The bank collects £800 over a period of 5 years in interest. __________ is the amount given on loan.

    >>> R a t e space o f space i n t e r e s t space equals space fraction numerator s i m p l e space i n t e r e s t cross times 100 over denominator p r i n c i p a l space a m o u n t cross times t i m e end fraction
    >>> p r i n c i p a l space a m o u n t space equals space fraction numerator s i m p l e space i n t e r e s t cross times 100 over denominator r a t e space o f space i n t e r e s t cross times t i m e end fraction
    >>>Principal amount = fraction numerator 800 cross times 100 over denominator 8 cross times 5 end fraction
    >>>Principal amount = 2000.

    A bank lends loan at 8% per year in simple interest. The bank collects £800 over a period of 5 years in interest. __________ is the amount given on loan.

    MathematicsGrade-7

    >>> R a t e space o f space i n t e r e s t space equals space fraction numerator s i m p l e space i n t e r e s t cross times 100 over denominator p r i n c i p a l space a m o u n t cross times t i m e end fraction
    >>> p r i n c i p a l space a m o u n t space equals space fraction numerator s i m p l e space i n t e r e s t cross times 100 over denominator r a t e space o f space i n t e r e s t cross times t i m e end fraction
    >>>Principal amount = fraction numerator 800 cross times 100 over denominator 8 cross times 5 end fraction
    >>>Principal amount = 2000.

    Grade-7
    Mathematics

    __________ is the rate of interest, if £40 is paid per year on a principal amount of £500.

    >>> Rate of interest = fraction numerator 40 cross times 100 over denominator 500 cross times 1 end fraction
    = 8 %.

    __________ is the rate of interest, if £40 is paid per year on a principal amount of £500.

    MathematicsGrade-7

    >>> Rate of interest = fraction numerator 40 cross times 100 over denominator 500 cross times 1 end fraction
    = 8 %.

    parallel
    Grade-7
    Mathematics

    If £200 is paid as interest towards a loan of £1000 over a period of 4 years, the rate of interest is _________.

    >>> R a t e space o f space i n t e r e s t space equals space fraction numerator S i m p l e space i n t e r e s t cross times 100 over denominator t i m e cross times p r i n c i p l e end fraction.
    >>> Rate of interest = fraction numerator 200 cross times 100 over denominator 4 cross times 1000 end fraction
    = 5 %

    If £200 is paid as interest towards a loan of £1000 over a period of 4 years, the rate of interest is _________.

    MathematicsGrade-7

    >>> R a t e space o f space i n t e r e s t space equals space fraction numerator S i m p l e space i n t e r e s t cross times 100 over denominator t i m e cross times p r i n c i p l e end fraction.
    >>> Rate of interest = fraction numerator 200 cross times 100 over denominator 4 cross times 1000 end fraction
    = 5 %

    Grade-7
    Mathematics

    _______ is the interest on $1200 principal at 2% per year for 10 years.

    _______ is the interest on $1200 principal at 2% per year for 10 years.

    MathematicsGrade-7
    Grade-7
    Mathematics

    Paul borrows £330 from a bank at 0.5% per annum and agrees to pay it back in 2 years. Determine the total amount to be paid back by him.

    Paul borrows £330 from a bank at 0.5% per annum and agrees to pay it back in 2 years. Determine the total amount to be paid back by him.

    MathematicsGrade-7
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.