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Mathematics

Grade6

Easy

Question

Lee had 7 green candies and 21 yellow candies. Clarke had 4 green candies and 7 yellow candies. __________ has the greater ratio of green to yellow candies

Lee
15:20
5:9
Clarke

hint Hint:

For comparing ratios, find out the lcm of denominator and make them equal, then compare the numerators.

The correct answer is: Clarke

Ratio of green to yellow candles Lee has = 7:21 = 1:3
Ratio of green to yellow candles Clarke has = 4:7
For comparing ratios, find out the lcm of denominator and make them equal, then compare the numerators.
$1 third a n d space 4 over 7 H e r e space L C M space o f space 3 space a n d space 7 space equals space 21 fraction numerator 1 cross times 7 over denominator 3 cross times 7 end fraction equals space 7 over 21 space a n d space fraction numerator 4 cross times 3 over denominator 7 cross times 3 end fraction equals space 12 over 21 H e r e comma space 7 less than 12 T h u s space 7 over 21 less than 12 over 21 T h u s comma space C l a r k e space h a s space g r e a t e r space r a t i o space g r e e n space t o space y e l l o w space c a n d l e s space t h a n space L e e.$

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