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Mathematics

Grade6

Easy

Question

Robert, a milkman, has $7 fraction numerator 2 over denominator 3 end fraction$ liters of milk. He wants to pour the milk into 5 bottles equally, then find the quantity of milk each bottle contains.

$1 \frac{8}{15}$ liters
$1 \frac{7}{15}$ liters
$2 \frac{8}{15}$ liters
$2 \frac{7}{15}$

hint Hint:

To find the quantity of milk for each bottle , we divide the total quantity of milk by number of bottles to be poured.

The correct answer is: $1 fraction numerator 8 over denominator 15 end fraction$ liters

Total quantity of milk Robert has = $7 fraction numerator 2 over denominator 3 end fraction$ liters ; Number of bottles = 5
Quantity of milk in each bottle = $7 2 over 3 space divided by space 5$
We can multiply the reciprocal of the denominator with the numerator to find the value of the problem.
$7 2 over 3 divided by 5 equals fraction numerator 3 cross times 7 plus 2 over denominator 3 end fraction cross times 1 fifth$ liters
$equals space 23 over 15 space equals 1 8 over 15$ liters per bottle.
Therefore, Quantity of milk in each bottle is $1 8 over 15 space$ liters.

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