Question
Select the expression equivalent to....
3(x) + 3(5)
- x + 5 + 3
- 3x + 30
- 3(x + 5)
- 3x + 5x + 3
Hint:
Both x and 5 is multiplied by 3
The correct answer is: 3(x + 5)
3(x) + 3(5) is equivalent to 3(x+5)
Related Questions to study
Select the algebraic expression to represent twenty-five added to a number p.
Select the algebraic expression to represent twenty-five added to a number p.
In the expression below the "9" labeled as?
4d-9
In the expression below the "9" labeled as?
4d-9
Ten more than four times a number
Ten more than four times a number
In the expression below, the "4" labeled as?
4d-9
In the expression below, the "4" labeled as?
4d-9
I open a saving account with $200 and plan to put $50 per month in the account. The expression represents this situation after x number of months?
I open a saving account with $200 and plan to put $50 per month in the account. The expression represents this situation after x number of months?
Use the distributive property to expand the expression: 4(y + 5x)
Given Expression:
4(y + 5x)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 4(y + 5x):
4(y + 5x)
= 
= 4y + 20x.
Hence, the expression 4(y + 5x) becomes 4y + 20x after it's expansion.
Use the distributive property to expand the expression: 4(y + 5x)
Given Expression:
4(y + 5x)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 4(y + 5x):
4(y + 5x)
=
= 4y + 20x.
Hence, the expression 4(y + 5x) becomes 4y + 20x after it's expansion.
Expand 2(8y + 15)
Given Expression:
2(8y + 15)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 2(8y + 15):
2(8y + 15)
= 2(8y + 15)
= 
= 16y + 30.
Hence, the given Expression 2(8y + 15) becomes 16y +30 after it's expansion.
Expand 2(8y + 15)
Given Expression:
2(8y + 15)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 2(8y + 15):
2(8y + 15)
= 2(8y + 15)
=
= 16y + 30.
Hence, the given Expression 2(8y + 15) becomes 16y +30 after it's expansion.
Simplify the following using distributive property of multiplication:
3(3y–4)
Given Expression:
3(3y–4)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 3(3y–4):
3(3y–4)
= 
= (9y) + (-12)
= 9y -12.
Hence, the expression 3(3y–4) becomes 9y -12 after it's expansion.
Simplify the following using distributive property of multiplication:
3(3y–4)
Given Expression:
3(3y–4)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 3(3y–4):
3(3y–4)
=
= (9y) + (-12)
= 9y -12.
Hence, the expression 3(3y–4) becomes 9y -12 after it's expansion.
Expand the following using distributive property of multiplication:
2(6x − 10)
Given Expression:
2(6x − 10)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 2(6x − 10) :
2(6x − 10)
= 
= (12x) + (-20)
= 12x -20.
Hence, the expression 2(6x − 10) becomes 12x -20 after it's expansion.
Expand the following using distributive property of multiplication:
2(6x − 10)
Given Expression:
2(6x − 10)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 2(6x − 10) :
2(6x − 10)
=
= (12x) + (-20)
= 12x -20.
Hence, the expression 2(6x − 10) becomes 12x -20 after it's expansion.
There were x cookies at the beginning of a party. By the end of the party, 16 of them had been eaten. Using x, write an expression for the number of cookies that were left.
There were x cookies at the beginning of a party. By the end of the party, 16 of them had been eaten. Using x, write an expression for the number of cookies that were left.
Expand the following using distributive property of multiplication: 5(6x − 11)
Given Expression:
5(6x − 11)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 5(6x − 11):
5(6x − 11)
= 
= (30x) + (-55)
= 30x -55.
Hence, the expression 5(6x − 11) becomes 30x -55 after expansion.
Expand the following using distributive property of multiplication: 5(6x − 11)
Given Expression:
5(6x − 11)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 5(6x − 11):
5(6x − 11)
=
= (30x) + (-55)
= 30x -55.
Hence, the expression 5(6x − 11) becomes 30x -55 after expansion.
Evaluate the expression for the given value of the variable.
3x + 5 when x = 5
Evaluate the expression for the given value of the variable.
3x + 5 when x = 5
Simplify the following using distributive property of multiplication:
9(3y–4)
Given Expression:
9(3y–4)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 9(3y–4):
9(3y–4)
= 
= (27y) + (-36)
= 27y - 36.
Hence, the expression 9(3y–4) becomes 27y-36 after expansion.
Simplify the following using distributive property of multiplication:
9(3y–4)
Given Expression:
9(3y–4)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 9(3y–4):
9(3y–4)
=
= (27y) + (-36)
= 27y - 36.
Hence, the expression 9(3y–4) becomes 27y-36 after expansion.
