Mathematics
Grade-7
Easy

Question

Simplify 2 open parentheses negative 1 over 6 close parentheses space plus space 3 open parentheses negative 1 fifth close parentheses space plus space 4 open parentheses negative 1 third close parentheses

  1. negative 34 over 15
  2. 6 over 13
  3. fraction numerator 6 over denominator negative 13 end fraction
  4. 13 over 6

Hint:

Simply following the BODMASS rule to solve the question.

The correct answer is: negative 34 over 15


    STEP BY STEP SOLUTION
    2 open parentheses negative 1 over 6 close parentheses space plus space 3 open parentheses negative 1 fifth close parentheses space plus space 4 open parentheses negative 1 third close parentheses
    M u l t i p l y i n g space a n d space o p e n i n g space b r a c k e t s space
    fraction numerator negative 2 over denominator 6 end fraction space minus space 3 over 5 space minus space 4 over 3
T a k i n g space L C M space o f space 6 comma 5 space & 3 space left parenthesis i. e space 30 right parenthesis
space equals space fraction numerator negative 10 space minus space 18 space minus space 40 over denominator 30 end fraction space equals space fraction numerator negative 68 over denominator 30 end fraction space equals space fraction numerator negative 34 over denominator 15 end fraction space

    Related Questions to study

    Grade-7
    Mathematics

    An elevator descends into a mine shaft from 3 6 over 10 above the ground level. If it goes 8 6 over 10 m below the ground level, find the distance covered by the elevator.

    STEP BY STEP SOLUTION
    Lift distance above ground = 3 6 over 10
    Lift distance below the ground = -8 6 over 10
    To calculate the total distance covered by life we will simple add the the distance below the ground and distance above the ground
    Distance covered by lift = 3 6 over 10 plus open vertical bar negative 8 6 over 10 close vertical bar equals 3 6 over 10 plus 8 6 over 10 equals 3.6 plus 8.6 equals 12.2
    So the total distance covered by lift = 12.2 units

    An elevator descends into a mine shaft from 3 6 over 10 above the ground level. If it goes 8 6 over 10 m below the ground level, find the distance covered by the elevator.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    Lift distance above ground = 3 6 over 10
    Lift distance below the ground = -8 6 over 10
    To calculate the total distance covered by life we will simple add the the distance below the ground and distance above the ground
    Distance covered by lift = 3 6 over 10 plus open vertical bar negative 8 6 over 10 close vertical bar equals 3 6 over 10 plus 8 6 over 10 equals 3.6 plus 8.6 equals 12.2
    So the total distance covered by lift = 12.2 units
    Grade-7
    Mathematics

    The quotient of  negative 10 over 4 space divided by space minus 0.2 is _________.

    STEP BY STEP SOLUTION
    fraction numerator negative 10 over denominator 4 end fraction space divided by space minus 0.2
C o n v e r t i n g space d e c i m a l space i n t o space f r a c t i o n
space equals space fraction numerator negative 10 over denominator 4 end fraction space divided by space fraction numerator negative 2 over denominator 10 end fraction space
D i v i d i n g space
equals space fraction numerator negative 10 over denominator 4 end fraction space cross times space fraction numerator negative 10 over denominator 2 end fraction space equals space 100 over 8 space equals space 25 over 2

    The quotient of  negative 10 over 4 space divided by space minus 0.2 is _________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    fraction numerator negative 10 over denominator 4 end fraction space divided by space minus 0.2
C o n v e r t i n g space d e c i m a l space i n t o space f r a c t i o n
space equals space fraction numerator negative 10 over denominator 4 end fraction space divided by space fraction numerator negative 2 over denominator 10 end fraction space
D i v i d i n g space
equals space fraction numerator negative 10 over denominator 4 end fraction space cross times space fraction numerator negative 10 over denominator 2 end fraction space equals space 100 over 8 space equals space 25 over 2
    Grade-7
    Mathematics

    The sum or difference of negative 28.3 minus open parentheses negative 4 1 third close parentheses is ___________.

    STEP BY STEP SOLUTION
    -28.3 + 4 1 third
    -28.3 + 13 over 3
    -28.3 + 4.3 = -24.0
    On simplyfying the above question we will get -24.0 as answer

    The sum or difference of negative 28.3 minus open parentheses negative 4 1 third close parentheses is ___________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    -28.3 + 4 1 third
    -28.3 + 13 over 3
    -28.3 + 4.3 = -24.0
    On simplyfying the above question we will get -24.0 as answer
    parallel
    Grade-7
    Mathematics

    Simply 10 over 8 left parenthesis 12 right parenthesis space plus space 12 open parentheses fraction numerator negative 6 over denominator 10 end fraction close parentheses

    STEP BY STEP SOLUTION
    10 over 8 left parenthesis 12 right parenthesis space plus space 12 open parentheses fraction numerator negative 6 over denominator 10 end fraction close parentheses
M u l t i p l y i n g space a n d space o p e n i n g space b r a c k e t s space
120 over 8 space minus 72 over 10
T a k i n g space L C M space o f space 8 space & space 10
fraction numerator 600 minus 288 over denominator 40 end fraction space equals space 312 over 40
equals 39 over 5

    Simply 10 over 8 left parenthesis 12 right parenthesis space plus space 12 open parentheses fraction numerator negative 6 over denominator 10 end fraction close parentheses

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    10 over 8 left parenthesis 12 right parenthesis space plus space 12 open parentheses fraction numerator negative 6 over denominator 10 end fraction close parentheses
M u l t i p l y i n g space a n d space o p e n i n g space b r a c k e t s space
120 over 8 space minus 72 over 10
T a k i n g space L C M space o f space 8 space & space 10
fraction numerator 600 minus 288 over denominator 40 end fraction space equals space 312 over 40
equals 39 over 5
    Grade-7
    Mathematics

    The sum or difference of negative 125.5 plus 4 1 half is ___________.

    STEP BY STEP SOLUTION
    negative 125.5 space plus 4 1 half
    Simplifyind the mixed fraction
    negative 125.5 space plus 9 over 2
    Now converting fraction into decimal
    negative 125.5 space plus space 4.5 = minus121.0
    On simplifying this we get the answer as -121.0

    The sum or difference of negative 125.5 plus 4 1 half is ___________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    negative 125.5 space plus 4 1 half
    Simplifyind the mixed fraction
    negative 125.5 space plus 9 over 2
    Now converting fraction into decimal
    negative 125.5 space plus space 4.5 = minus121.0
    On simplifying this we get the answer as -121.0
    Grade-7
    Mathematics

    If a number is divided by 11 over 3 to negative 3 over 19. The number is _________.

    STEP BY STEP SOLUTION
    Let the number be x
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    x space divided by 11 over 13 space equals space fraction numerator negative 3 over denominator 19 end fraction
    x space equals space fraction numerator negative 3 over denominator 19 end fraction space cross times 11 over 13
x space equals space minus 33 over 247
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    If a number is divided by 11 over 3 to negative 3 over 19. The number is _________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    Let the number be x
    If a number divided by 11 over 13 to give fraction numerator negative 3 over denominator 19 end fraction
    x space divided by 11 over 13 space equals space fraction numerator negative 3 over denominator 19 end fraction
    x space equals space fraction numerator negative 3 over denominator 19 end fraction space cross times 11 over 13
x space equals space minus 33 over 247
    HENCE, THE NUMBER IS negative 33 over 247
    parallel
    Grade-7
    Mathematics

    The sum or difference of negative 5.5 minus open parentheses negative 3 1 half close parentheses is _____________.

    STEP BY STEP SOLUTION
    negative 5.5 space plus space 3 1 half
    Converting mixed fraction into simple fraction
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    Taking LCM
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    The sum or difference of negative 5.5 minus open parentheses negative 3 1 half close parentheses is _____________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    negative 5.5 space plus space 3 1 half
    Converting mixed fraction into simple fraction
    negative 5.5 space plus 7 over 2
    Taking LCM
    fraction numerator negative 11 plus 7 over denominator 2 end fraction = fraction numerator negative 4 over denominator 2 end fraction equals negative 2
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    An airplane covers 1020 miles in an hour. Distance covered by it in 25 over 6 hours is __________ miles.

    STEP SBY STEP SOLUTION
    Distance covered by aeroplane oin 1 hour = 1020 miles
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    space 1 space h o u r space equals space 1020 space m i l e s space
space fraction numerator 25 over denominator 6 space end fraction space h o u r s space equals space 1020 space divided by 25 over 6
    space 1020 over 1 space divided by space 25 over 6
space equals space 1020 over 1 space cross times space 6 over 25
space equals space 6120 over 25
space equals space 1224 over 5
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    STEP SBY STEP SOLUTION
    Distance covered by aeroplane oin 1 hour = 1020 miles
    Distance covered by aeroplane in fraction numerator 25 over denominator 6 space end fraction space h o u r s space equals space ?
    space 1 space h o u r space equals space 1020 space m i l e s space
space fraction numerator 25 over denominator 6 space end fraction space h o u r s space equals space 1020 space divided by 25 over 6
    space 1020 over 1 space divided by space 25 over 6
space equals space 1020 over 1 space cross times space 6 over 25
space equals space 6120 over 25
space equals space 1224 over 5
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    Mathematics

    The value of  8 open parentheses fraction numerator negative 2 over denominator 3 end fraction close parentheses space minus space 8 open parentheses fraction numerator negative 6 over denominator 4 end fraction close parentheses is __________.

    STEP BY STEP SOLUTION
    \]8 open parentheses fraction numerator negative 2 over denominator 3 end fraction close parentheses space minus space 8 open parentheses fraction numerator negative 6 over denominator 4 end fraction close parentheses space
M u l t i p l y i n g space a n d space o p e n i n g space b r a c k e t s space
fraction numerator negative 16 over denominator 3 end fraction space plus space 48 over 4
T a k i n g space L C M space o f space 3 & 4 space left parenthesis i. e space 12 right parenthesis
fraction numerator negative 64 space plus 144 space over denominator 12 end fraction
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    The value of  8 open parentheses fraction numerator negative 2 over denominator 3 end fraction close parentheses space minus space 8 open parentheses fraction numerator negative 6 over denominator 4 end fraction close parentheses is __________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    \]8 open parentheses fraction numerator negative 2 over denominator 3 end fraction close parentheses space minus space 8 open parentheses fraction numerator negative 6 over denominator 4 end fraction close parentheses space
M u l t i p l y i n g space a n d space o p e n i n g space b r a c k e t s space
fraction numerator negative 16 over denominator 3 end fraction space plus space 48 over 4
T a k i n g space L C M space o f space 3 & 4 space left parenthesis i. e space 12 right parenthesis
fraction numerator negative 64 space plus 144 space over denominator 12 end fraction
80 over 12 space equals space 20 over 3
    parallel
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    Mathematics

    The sum or difference of  negative 13 over 12 minus open parentheses fraction numerator negative 8 over denominator 12 end fraction close parentheses  is _____________.

    STEP BY STEP SOLUTION
    fraction numerator negative 13 over denominator 12 end fraction space plus space 8 over 12
T a k i n g space t h e space L C M thin space o f space t h e space a b o v e space t w o space f r a c t i o n space
fraction numerator negative 13 space plus space 8 over denominator 12 end fraction
N o w space s i m p l i f y i n g space t h e space q u e s t i o n space
fraction numerator negative 5 over denominator 12 end fraction
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    The sum or difference of  negative 13 over 12 minus open parentheses fraction numerator negative 8 over denominator 12 end fraction close parentheses  is _____________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    fraction numerator negative 13 over denominator 12 end fraction space plus space 8 over 12
T a k i n g space t h e space L C M thin space o f space t h e space a b o v e space t w o space f r a c t i o n space
fraction numerator negative 13 space plus space 8 over denominator 12 end fraction
N o w space s i m p l i f y i n g space t h e space q u e s t i o n space
fraction numerator negative 5 over denominator 12 end fraction
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    Grade-7
    Mathematics

    The value of  2 left parenthesis 0.6 right parenthesis space plus space open parentheses fraction numerator negative 1 over denominator 9 end fraction close parentheses is ___________.

    STEP BY STEP SOLUTION
    2 left parenthesis 0.6 right parenthesis space plus space open parentheses negative 1 over 9 close parentheses space
C o n v e r t i n g space d e c i m a l space i n t o space f r a c t i o n space
equals space 2 space cross times space 6 over 10 space plus space open parentheses negative 1 over 9 close parentheses space
M u l t i p l y i n g space a n d space o p e n i n g space b r a c k e t space
equals space 12 over 10 space minus space 1 over 9 space
T a k i n g space L C M thin space o f space 10 space & space 9 space left parenthesis i. e space 90 right parenthesis
fraction numerator 108 space minus space 10 space over denominator 90 end fraction space equals fraction numerator space 98 over denominator 90 end fraction space equals space 49 over 45

    The value of  2 left parenthesis 0.6 right parenthesis space plus space open parentheses fraction numerator negative 1 over denominator 9 end fraction close parentheses is ___________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    2 left parenthesis 0.6 right parenthesis space plus space open parentheses negative 1 over 9 close parentheses space
C o n v e r t i n g space d e c i m a l space i n t o space f r a c t i o n space
equals space 2 space cross times space 6 over 10 space plus space open parentheses negative 1 over 9 close parentheses space
M u l t i p l y i n g space a n d space o p e n i n g space b r a c k e t space
equals space 12 over 10 space minus space 1 over 9 space
T a k i n g space L C M thin space o f space 10 space & space 9 space left parenthesis i. e space 90 right parenthesis
fraction numerator 108 space minus space 10 space over denominator 90 end fraction space equals fraction numerator space 98 over denominator 90 end fraction space equals space 49 over 45
    Grade-7
    Mathematics

    The sum or difference of  negative 2 over 3 plus 4 over 3 is __________.

    STEP  BY STEP SOLUTION
    negative 2 over 3 plus space 4 over 3
T a k i n g space L C M thin space
fraction numerator negative 2 plus 4 over denominator 3 end fraction space equals space 2 over 3
    The answerof this question is 2 over 3

    The sum or difference of  negative 2 over 3 plus 4 over 3 is __________.

    MathematicsGrade-7
    STEP  BY STEP SOLUTION
    negative 2 over 3 plus space 4 over 3
T a k i n g space L C M thin space
fraction numerator negative 2 plus 4 over denominator 3 end fraction space equals space 2 over 3
    The answerof this question is 2 over 3
    parallel
    Grade-7
    Mathematics

    Simplify 2 open parentheses negative 1 third close parentheses space plus space 3 open parentheses negative 1 fourth close parentheses space plus space 1 open parentheses fraction numerator negative 1 over denominator 2 end fraction close parentheses

    STEP BY STEP SOLUTION
    2 open parentheses negative 1 third close parentheses space plus space 3 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses space plus space 1 open parentheses fraction numerator negative 1 over denominator 2 end fraction close parentheses space
O p e n i n g space b r a c k e t s space a n d space m u l t i p l y i n g space
equals space fraction numerator negative 2 over denominator 3 end fraction space minus space 3 over 4 space minus space 1 half
T a k i n g space L C M space o f space 3 comma 4 & 2 space left parenthesis i. e space 12 right parenthesis
space equals space fraction numerator negative 8 space minus space 9 space minus space 6 over denominator 12 end fraction space equals space fraction numerator negative 23 over denominator 12 end fraction

    Simplify 2 open parentheses negative 1 third close parentheses space plus space 3 open parentheses negative 1 fourth close parentheses space plus space 1 open parentheses fraction numerator negative 1 over denominator 2 end fraction close parentheses

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    2 open parentheses negative 1 third close parentheses space plus space 3 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses space plus space 1 open parentheses fraction numerator negative 1 over denominator 2 end fraction close parentheses space
O p e n i n g space b r a c k e t s space a n d space m u l t i p l y i n g space
equals space fraction numerator negative 2 over denominator 3 end fraction space minus space 3 over 4 space minus space 1 half
T a k i n g space L C M space o f space 3 comma 4 & 2 space left parenthesis i. e space 12 right parenthesis
space equals space fraction numerator negative 8 space minus space 9 space minus space 6 over denominator 12 end fraction space equals space fraction numerator negative 23 over denominator 12 end fraction
    Grade-7
    Mathematics

    The sum or difference of negative 5.5 minus open parentheses negative 3 1 half close parentheses is _________.

    STEP BY STEP SOLUTION
    negative 5.5 minus open parentheses negative 3 1 half close parentheses
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals negative 5.5 space minus space open parentheses negative 7 over 2 close parentheses
O p e n i n g space b r a c k e t space
equals space minus 5.5 space plus 7 over 2
C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l space o r space t a k i n g space L C M space
equals negative 5.5 plus 3.5 equals negative 2.0
T h e space a n s w e r space o f space a b o v e space q u e s t i o n space i s space minus 2.0

    The sum or difference of negative 5.5 minus open parentheses negative 3 1 half close parentheses is _________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    negative 5.5 minus open parentheses negative 3 1 half close parentheses
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals negative 5.5 space minus space open parentheses negative 7 over 2 close parentheses
O p e n i n g space b r a c k e t space
equals space minus 5.5 space plus 7 over 2
C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l space o r space t a k i n g space L C M space
equals negative 5.5 plus 3.5 equals negative 2.0
T h e space a n s w e r space o f space a b o v e space q u e s t i o n space i s space minus 2.0
    Grade-7
    Mathematics

    The value of  2 open parentheses negative 4 over 3 close parentheses space divided by space 2 open parentheses negative 6 over 9 close parentheses is _________.

    STEP BY STEP SOLUTION
    2 open parentheses fraction numerator negative 4 over denominator 3 end fraction close parentheses space minus space 2 open parentheses fraction numerator negative 6 over denominator 9 end fraction close parentheses space
M u l t i p l y i n g space 2 space a n d space o p e n i n g space b r a c k e t
equals space minus 8 over 3 space plus 12 over 9 space
T a k i n g space L C M thin space o f space 3 & 9 space left parenthesis i. e space 9 right parenthesis
equals space fraction numerator negative 24 space plus 12 over denominator 9 end fraction space
equals negative space 12 over 9 space equals negative space fraction numerator 4 over denominator space 3 end fraction

    The value of  2 open parentheses negative 4 over 3 close parentheses space divided by space 2 open parentheses negative 6 over 9 close parentheses is _________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    2 open parentheses fraction numerator negative 4 over denominator 3 end fraction close parentheses space minus space 2 open parentheses fraction numerator negative 6 over denominator 9 end fraction close parentheses space
M u l t i p l y i n g space 2 space a n d space o p e n i n g space b r a c k e t
equals space minus 8 over 3 space plus 12 over 9 space
T a k i n g space L C M thin space o f space 3 & 9 space left parenthesis i. e space 9 right parenthesis
equals space fraction numerator negative 24 space plus 12 over denominator 9 end fraction space
equals negative space 12 over 9 space equals negative space fraction numerator 4 over denominator space 3 end fraction
    parallel

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