Mathematics
Grade-7
Easy

Question

Solve 1 + 3f ≤ 7

  1. f ≤ 2
  2. f > 2
  3. f < 2
  4. f > 2

hintHint:

ultimate goal is to find f , so we need to remove 1, and 3 from 1+3f, so that we get f

The correct answer is: f ≤ 2


    1 + 3f ≤ 7
    1 + 3f – 1 ≤ 7 - 1 Subtract 1 from both sides
    3f ≤ 6 Simplify
    fraction numerator 3 f over denominator 3 end fraction less or equal than 6 over 3 Divide both sides by 3
    f ≤ 2 Simplify

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