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Mathematics

Grade-7

Easy

Question

Solve 6t + 4 ≤ - 2.

t ≤ - 1
t ≤ 1
t = 1
1 = t

hint Hint:

we have to find t, so we have to remove 4 from 6t+4, first by substracting 4 from both side, now we get 6t, now we have to remove 6 from 6t by dividing by 6 from both side, now we get t

The correct answer is: t ≤ - 1

6t + 4 ≤ - 2
6t + 4 - 4 ≤ - 2 – 4 Subtract 4 from both sides.
6t ≤ - 6
$fraction numerator 6 t over denominator 6 end fraction less or equal than fraction numerator negative 6 over denominator 6 end fraction$ Divided both sides by 6.
t ≤ - 1

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