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Mathematics

Grade10

Easy

Question

Solve for y.
$straight x space equals space 3 left parenthesis cube root of 15 space plus space straight y end root right parenthesis$

x³ – 27
$(\frac{x^{3}}{3}) - 10$
$15 - (\frac{x^{3}}{9})$
$(\frac{x^{3}}{27}) - 15$

hint Hint:

In this question, we have to find the value of y if $straight x space equals space 3 left parenthesis cube root of 15 space plus space straight y end root right parenthesis$ . For this we have to equate the given equation. Firstly, we will cross multiply the equation, then cube both the sides and later solve the equation further to get y.

The correct answer is: $open parentheses straight x cubed over 27 close parentheses space minus space 15$

$As space per space question comma space straight x space equals space 3 left parenthesis cube root of 15 space plus space straight y end root right parenthesis C r o s s space m u l t i p l y i n g comma space rightwards double arrow x over 3 equals space cube root of 15 space plus space straight y end root C u b i n g space b o t h space t h e space s i d e s comma rightwards double arrow left parenthesis x over 3 right parenthesis cubed equals left parenthesis cube root of 15 plus y end root right parenthesis cubed rightwards double arrow x cubed over 27 equals 15 plus y not stretchy rightwards double arrow space straight y space equals space straight x cubed over 27 space minus space 15 H e n c e comma space space straight y space equals space straight x cubed over 27 space minus space 15$

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