Mathematics
Grade6
Easy

Question

Solve the following equation using additive property of equality.
w minus 4 fraction numerator 3 over denominator 8 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction

  1. 6 fraction numerator 1 over denominator 2 end fraction    
  2. 6    
  3. 6 fraction numerator 7 over denominator 8 end fraction    
  4. 7 fraction numerator 7 over denominator 8 end fraction    

The correct answer is: 6 fraction numerator 7 over denominator 8 end fraction


    Step 1:
    w minus 4 fraction numerator 3 over denominator 8 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction
    Using additive property of equality, add (4 fraction numerator 3 over denominator 8 end fraction) to both sides
    Step 2:
    W minus 4 fraction numerator 3 over denominator 8 end fraction plus 4 fraction numerator 3 over denominator 8 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction plus 4 fraction numerator 3 over denominator 8 end fraction
    Then we get, w equals 6 fraction numerator 7 over denominator 8 end fraction

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