Mathematics
Grade6
Easy

Question

Solve the following equation using additive property of equality.
w minus 8 fraction numerator 1 over denominator 2 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction

  1. 8    
  2. 9    
  3. 10    
  4. 11    

The correct answer is: 11


    Step 1:
    w minus 8 fraction numerator 1 over denominator 2 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction
    Using additive property of equality add 8fraction numerator 1 over denominator 2 end fraction to both sides
    Step 2:
    w minus 8 fraction numerator 1 over denominator 2 end fraction plus 8 fraction numerator 1 over denominator 2 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction plus 8 fraction numerator 1 over denominator 2 end fraction equals 11
    So, w = 11

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