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    Mathematics
    Grade6
    Easy

    Question

    Solve the following equation using additive property of equality.
    w minus 8 fraction numerator 1 over denominator 2 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction

    1. 8    
    2. 9    
    3. 10    
    4. 11    

    The correct answer is: 11

      Step 1:
      w minus 8 fraction numerator 1 over denominator 2 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction
      Using additive property of equality add 8fraction numerator 1 over denominator 2 end fraction to both sides
      Step 2:
      w minus 8 fraction numerator 1 over denominator 2 end fraction plus 8 fraction numerator 1 over denominator 2 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction plus 8 fraction numerator 1 over denominator 2 end fraction equals 11
      So, w = 11

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