Mathematics
Easy

Question

# Solve the system:y = -2x + 202x + y = 10

## No solution(11, 8)(5, 15)Infinitely many solutions Hint:

## The correct answer is: No solution

### Here we have solve the system of equation and find x and y.Firstly , we are given, y = -2x + 20 and 2x + y = 10So we can write,y = -2x + 20 -------( 1)2x + y = 10 --------(2)Now , we have a1/a2 a1/a2 = 2/2 =1and b1/b2 ,b1/b2 = 1/1 = 1and c1/c2c1/c2 = 20/10= 2so here,1 = 1 ≠ 2 a1/a2 = b1/b2 ≠ c1/c2Therefore, the system of equation of no solution.The correct answer is No solution.Or Another way to solve the question,y = -2x + 20 …(i)2x + y = 10 …(ii)Substituting y from (i) in (ii), we get 2x + (-2x + 20) = 1020 = 10The statement 20 = 10 is false, so the system of equations has no solution.

In this question, we have to find the system of equation. If (a1/a2) = (b1/b2) = (c1/c2) then it is infinitely many solutions, if  (a1/a2) = (b1/b2) ≠ (c1/c2) and if (a1/a2) ≠(b1/b2) then it is unique solution.

### Related Questions to study  #### With Turito Foundation. #### Get an Expert Advice From Turito.  