Solve the system:
y = -2x + 20
2x + y = 10

The correct answer is: No solution

Here we have solve the system of equation and find x and y.
Firstly , we are given, y = -2x + 20 and 2x + y = 10
So we can write,
y = -2x + 20 -------( 1)
2x + y = 10 --------(2)
Now , we have a1/a2
a1/a2 = 2/2 =1
and b1/b2 ,
b1/b2 = 1/1 = 1
and c1/c2
c1/c2 = 20/10= 2
so here,
1 = 1 ≠ 2
a1/a2 = b1/b2 ≠ c1/c2
Therefore, the system of equation of no solution.
The correct answer is No solution.
Or Another way to solve the question,
y = -2x + 20 …(i)
2x + y = 10 …(ii)
Substituting y from (i) in (ii), we get
2x + (-2x + 20) = 10
20 = 10
The statement 20 = 10 is false, so the system of equations has no solution.

In this question, we have to find the system of equation. If (a1/a2) = (b1/b2) = (c1/c2) then it is infinitely many solutions, if  (a1/a2) = (b1/b2) ≠ (c1/c2) and if (a1/a2) ≠(b1/b2) then it is unique solution.